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View Full Version : Doppler Distortion - A Question In Classical Physics


Bob Cain
Aug7-04, 05:07 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>The audio community at large believes in a phenomenon\nexhibited by loudspeakers called "Doppler Distortion". I\nhave my doubts for a number of reasons but I cannot get my\nhead around what I would consider a satisfactory answer.\n\nThe question I have is what is the pressure function of time\ndescribing a wave propegating off the interface between air\nand a stiff, massless, infinite compliant piston mounted in\na doubly infinite tube as a function of the force function\nof time applied to the piston.\n\nPeople claim that because it is moving in the medium, it is\nnon-linear in a way that will introduce frequency modulation\nif just two sinusoids are summed and presented to the\nsystem. I don\'t think so but can\'t prove it. Any help from\nthis august group will be highly appreciated.\n\nA leather hat meal is at stake here. :-)\n\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>The audio community at large believes in a phenomenon
exhibited by loudspeakers called "Doppler Distortion". I
have my doubts for a number of reasons but I cannot get my
head around what I would consider a satisfactory answer.

The question I have is what is the pressure function of time
describing a wave propegating off the interface between air
and a stiff, massless, infinite compliant piston mounted in
a doubly infinite tube as a function of the force function
of time applied to the piston.

People claim that because it is moving in the medium, it is
non-linear in a way that will introduce frequency modulation
if just two sinusoids are summed and presented to the
system. I don't think so but can't prove it. Any help from
this august group will be highly appreciated.

A leather hat meal is at stake here. :-)


Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein

ZZBunker
Aug12-04, 08:29 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n\nBob Cain &lt;arcane@arcanemethods.com&gt; wrote in message news:&lt;cf1pc102d0i@enews3.newsguy.com&gt;...\n&gt; The audio community at large believes in a phenomenon\n&gt; exhibited by loudspeakers called "Doppler Distortion". I\n&gt; have my doubts for a number of reasons but I cannot get my\n&gt; head around what I would consider a satisfactory answer.\n&gt;\n&gt; The question I have is what is the pressure function of time\n&gt; describing a wave propegating off the interface between air\n&gt; and a stiff, massless, infinite compliant piston mounted in\n&gt; a doubly infinite tube as a function of the force function\n&gt; of time applied to the piston.\n&gt;\n&gt; People claim that because it is moving in the medium, it is\n&gt; non-linear in a way that will introduce frequency modulation\n&gt; if just two sinusoids are summed and presented to the\n&gt; system. I don\'t think so but can\'t prove it. Any help from\n&gt; this august group will be highly appreciated.\n&gt;\n&gt; A leather hat meal is at stake here. :-)\n\nWell, it\'s true, but not for the reason the Audio Community\nsays it\'s true. The infinte piston model they use itself assumes\nthe piston is actually electro-static, not mechanically-compliant.\n\nBut when you go about actually building an electro-static\npiston, you\'ll find that they have frequency modulation\nbuild into them. Which is the reason digital sound\nsystems actually work.\n\nThere is no frequency modulation is naturally compliant\nmaterials like the Earth\'s Crust or the Ocean.\nWhich is where the original analysis of the Doppler Effect\ncame from.\n\n\n\n&gt;\n&gt;\n&gt; Bob\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Bob Cain <arcane@arcanemethods.com> wrote in message news:<cf1pc102d0i@enews3.newsguy.com>...
> The audio community at large believes in a phenomenon
> exhibited by loudspeakers called "Doppler Distortion". I
> have my doubts for a number of reasons but I cannot get my
> head around what I would consider a satisfactory answer.
>
> The question I have is what is the pressure function of time
> describing a wave propegating off the interface between air
> and a stiff, massless, infinite compliant piston mounted in
> a doubly infinite tube as a function of the force function
> of time applied to the piston.
>
> People claim that because it is moving in the medium, it is
> non-linear in a way that will introduce frequency modulation
> if just two sinusoids are summed and presented to the
> system. I don't think so but can't prove it. Any help from
> this august group will be highly appreciated.
>
> A leather hat meal is at stake here. :-)

Well, it's true, but not for the reason the Audio Community
says it's true. The infinte piston model they use itself assumes
the piston is actually electro-static, not mechanically-compliant.

But when you go about actually building an electro-static
piston, you'll find that they have frequency modulation
build into them. Which is the reason digital sound
systems actually work.

There is no frequency modulation is naturally compliant
materials like the Earth's Crust or the Ocean.
Which is where the original analysis of the Doppler Effect
came from.



>
>
> Bob

Danny Ross Lunsford
Aug12-04, 08:29 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n\nBob Cain &lt;arcane@arcanemethods.com&gt; wrote in message news:&lt;cf1pc102d0i@enews3.newsguy.com&gt;...\n&gt; The audio community at large believes in a phenomenon\n&gt; exhibited by loudspeakers called "Doppler Distortion". I\n&gt; have my doubts for a number of reasons but I cannot get my\n&gt; head around what I would consider a satisfactory answer.\n&gt;\n&gt; The question I have is what is the pressure function of time\n&gt; describing a wave propegating off the interface between air\n&gt; and a stiff, massless, infinite compliant piston mounted in\n&gt; a doubly infinite tube as a function of the force function\n&gt; of time applied to the piston.\n&gt;\n&gt; People claim that because it is moving in the medium, it is\n&gt; non-linear in a way that will introduce frequency modulation\n&gt; if just two sinusoids are summed and presented to the\n&gt; system. I don\'t think so but can\'t prove it. Any help from\n&gt; this august group will be highly appreciated.\n&gt;\n&gt; A leather hat meal is at stake here. :-)\n\nI think that whatever this effect is, it can\'t be very important for\nsound. I think this was first investigated by Helmholtz ("On the\nSensations of Tone").\n\nAs far as sound goes, certainly viscosity, mass flow etc. introduce\nmore or less complex terms into the wave equation, that may or may not\nbe important for sound perception in ordinary circumstances.\n\n-drl\n\n&gt;\n&gt;\n&gt; Bob\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Bob Cain <arcane@arcanemethods.com> wrote in message news:<cf1pc102d0i@enews3.newsguy.com>...
> The audio community at large believes in a phenomenon
> exhibited by loudspeakers called "Doppler Distortion". I
> have my doubts for a number of reasons but I cannot get my
> head around what I would consider a satisfactory answer.
>
> The question I have is what is the pressure function of time
> describing a wave propegating off the interface between air
> and a stiff, massless, infinite compliant piston mounted in
> a doubly infinite tube as a function of the force function
> of time applied to the piston.
>
> People claim that because it is moving in the medium, it is
> non-linear in a way that will introduce frequency modulation
> if just two sinusoids are summed and presented to the
> system. I don't think so but can't prove it. Any help from
> this august group will be highly appreciated.
>
> A leather hat meal is at stake here. :-)

I think that whatever this effect is, it can't be very important for
sound. I think this was first investigated by Helmholtz ("On the
Sensations of Tone").

As far as sound goes, certainly viscosity, mass flow etc. introduce
more or less complex terms into the wave equation, that may or may not
be important for sound perception in ordinary circumstances.

-drl

>
>
> Bob

Norm Dresner
Aug12-04, 08:29 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n"Bob Cain" &lt;arcane@arcanemethods.com&gt; wrote in message\nnews:cf1pc102d0i@enews3.newsguy.com...\n&gt; The audio community at large believes in a phenomenon\n&gt; exhibited by loudspeakers called "Doppler Distortion". I\n&gt; have my doubts for a number of reasons but I cannot get my\n&gt; head around what I would consider a satisfactory answer.\n&gt;\n\nPlease don\'t skewer the "audio community at large" because of the beliefs of\na few misbegotten souls. These are generally the same folks who believe\nthat speaker cables are directional (i.e. sound better transmitting an AC\nwaveform in one in one direction from the amplifier to the speaker than in\nthe other direction) because of "micro crystalline diodes" in the metal in\nthe wires. There is probably no limit to the number of bizarre beliefs that\nthese people can invent to either excuse their misbehaving equipment or\njustify buying something new. AFAIK sound is a longitudinal wave\npropagating in a compressible medium. (In general) It has to be created by\nsome moving surface; it is originally when the sounds that they\'re trying to\nreproduce are recorded.\n\nNorm\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"Bob Cain" <arcane@arcanemethods.com> wrote in message
news:cf1pc102d0i@enews3.newsguy.com...
> The audio community at large believes in a phenomenon
> exhibited by loudspeakers called "Doppler Distortion". I
> have my doubts for a number of reasons but I cannot get my
> head around what I would consider a satisfactory answer.
>

Please don't skewer the "audio community at large" because of the beliefs of
a few misbegotten souls. These are generally the same folks who believe
that speaker cables are directional (i.e. sound better transmitting an AC
waveform in one in one direction from the amplifier to the speaker than in
the other direction) because of "micro crystalline diodes" in the metal in
the wires. There is probably no limit to the number of bizarre beliefs that
these people can invent to either excuse their misbehaving equipment or
justify buying something new. AFAIK sound is a longitudinal wave
propagating in a compressible medium. (In general) It has to be created by
some moving surface; it is originally when the sounds that they're trying to
reproduce are recorded.

Norm

Franz Heymann
Aug12-04, 08:29 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n\n"Bob Cain" &lt;arcane@arcanemethods.com&gt; wrote in message\nnews:cf1pc102d0i@enews3.newsguy.com...\n&gt; The audio community at large believes in a phenomenon\n&gt; exhibited by loudspeakers called "Doppler Distortion". I\n&gt; have my doubts for a number of reasons but I cannot get my\n&gt; head around what I would consider a satisfactory answer.\n&gt;\n&gt; The question I have is what is the pressure function of time\n&gt; describing a wave propegating off the interface between air\n&gt; and a stiff, massless, infinite compliant piston mounted in\n&gt; a doubly infinite tube as a function of the force function\n&gt; of time applied to the piston.\n&gt;\n&gt; People claim that because it is moving in the medium, it is\n&gt; non-linear in a way that will introduce frequency modulation\n&gt; if just two sinusoids are summed and presented to the\n&gt; system. I don\'t think so but can\'t prove it. Any help from\n&gt; this august group will be highly appreciated.\n&gt;\n&gt; A leather hat meal is at stake here. :-)\n\nThe answer to your problem lies in the fact that the radiation\nimpedance of a vibrating piston is not equal to the acoustic\nimpedance seen by a propagating wave. The latter is a pure acoustic\nresistance, independent of frequency. The former contains an acoustic\ninductance as well as an acoustic resistance, both of which are\nfunctions of frequency. In particular, at very low frequencies, the\ndiaphragm has to vibrate with a much larger acoustic current than at\nhigher frequencies, for a given power output. It is this "excess"\nvelocity of the diaphragm which is responsible for the Doppler\ndistortion.\n\nFranz\n\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"Bob Cain" <arcane@arcanemethods.com> wrote in message
news:cf1pc102d0i@enews3.newsguy.com...
> The audio community at large believes in a phenomenon
> exhibited by loudspeakers called "Doppler Distortion". I
> have my doubts for a number of reasons but I cannot get my
> head around what I would consider a satisfactory answer.
>
> The question I have is what is the pressure function of time
> describing a wave propegating off the interface between air
> and a stiff, massless, infinite compliant piston mounted in
> a doubly infinite tube as a function of the force function
> of time applied to the piston.
>
> People claim that because it is moving in the medium, it is
> non-linear in a way that will introduce frequency modulation
> if just two sinusoids are summed and presented to the
> system. I don't think so but can't prove it. Any help from
> this august group will be highly appreciated.
>
> A leather hat meal is at stake here. :-)

The answer to your problem lies in the fact that the radiation
impedance of a vibrating piston is not equal to the acoustic
impedance seen by a propagating wave. The latter is a pure acoustic
resistance, independent of frequency. The former contains an acoustic
inductance as well as an acoustic resistance, both of which are
functions of frequency. In particular, at very low frequencies, the
diaphragm has to vibrate with a much larger acoustic current than at
higher frequencies, for a given power output. It is this "excess"
velocity of the diaphragm which is responsible for the Doppler
distortion.

Franz

Bob Cain
Aug14-04, 06:58 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\nNorm Dresner wrote:\n\n&gt; Please don\'t skewer the "audio community at large" because of the beliefs of\n&gt; a few misbegotten souls. These are generally the same folks who believe\n&gt; that speaker cables are directional (i.e. sound better transmitting an AC\n&gt; waveform in one in one direction from the amplifier to the speaker than in\n&gt; the other direction) because of "micro crystalline diodes" in the metal in\n&gt; the wires. There is probably no limit to the number of bizarre beliefs that\n&gt; these people can invent to either excuse their misbehaving equipment or\n&gt; justify buying something new. AFAIK sound is a longitudinal wave\n&gt; propagating in a compressible medium. (In general) It has to be created by\n&gt; some moving surface; it is originally when the sounds that they\'re trying to\n&gt; reproduce are recorded.\n\nNo, I wouldn\'t skewer them. I am one. Just one with a bit\nmore of a technical education.\n\nThe simple argument I\'ve been using to disprove the\nphenomenon boils down to whether or not the principle of\nreciprocity applies to acoustic systems, whether the motion\nof an ideal test piston (zero mechanical impedence) in an\ninfinite waveguide, a tube, with a plane wave traveling in\nit will be the same motion as that of a piston creating that\nwave but with a delay. Seems obvious to me and I think, but\nam not sure, that this reciprocity can be proved by an\nappeal to the conservation of energy.\n\nIf so, I\'ve put a nail in the coffin of something widely\nbelieved but justified by an argument with no rigor at all,\nwhich is unable to provide a predictive theory for general\nsignals but is nonetheless found very persuasive. It\'s\nnever sat right with me and I only recently decided to\nfigure out why.\n\nThen again, maybe I\'m wrong. My head is sticking out really\nfar among my peers in audio but life\'s no fun without taking\nchances. :-)\n\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Norm Dresner wrote:

> Please don't skewer the "audio community at large" because of the beliefs of
> a few misbegotten souls. These are generally the same folks who believe
> that speaker cables are directional (i.e. sound better transmitting an AC
> waveform in one in one direction from the amplifier to the speaker than in
> the other direction) because of "micro crystalline diodes" in the metal in
> the wires. There is probably no limit to the number of bizarre beliefs that
> these people can invent to either excuse their misbehaving equipment or
> justify buying something new. AFAIK sound is a longitudinal wave
> propagating in a compressible medium. (In general) It has to be created by
> some moving surface; it is originally when the sounds that they're trying to
> reproduce are recorded.

No, I wouldn't skewer them. I am one. Just one with a bit
more of a technical education.

The simple argument I've been using to disprove the
phenomenon boils down to whether or not the principle of
reciprocity applies to acoustic systems, whether the motion
of an ideal test piston (zero mechanical impedence) in an
infinite waveguide, a tube, with a plane wave traveling in
it will be the same motion as that of a piston creating that
wave but with a delay. Seems obvious to me and I think, but
am not sure, that this reciprocity can be proved by an
appeal to the conservation of energy.

If so, I've put a nail in the coffin of something widely
believed but justified by an argument with no rigor at all,
which is unable to provide a predictive theory for general
signals but is nonetheless found very persuasive. It's
never sat right with me and I only recently decided to
figure out why.

Then again, maybe I'm wrong. My head is sticking out really
far among my peers in audio but life's no fun without taking
chances. :-)


Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein

Bob Cain
Aug16-04, 12:55 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n\nBob Cain wrote:\n\n\n&gt; No, I wouldn\'t skewer them. I am one. Just one with a bit\n&gt; more of a technical education.\n&gt;\n&gt; The simple argument I\'ve been using to disprove the\n&gt; phenomenon boils down to whether or not the principle of\n&gt; reciprocity applies to acoustic systems,\n\nFWIW, I think I\'ve found an even simpler argument that\nillustrates the flaw in the vernacular argument for "Doppler\ndistortion" that has survived for so long. That argement\ndepends on the origin of the wave moving in time. It\ndoesn\'t. The origin of the wave is the rest position of the\npiston. The magnitude of the wave that propegates is the\nvolume velocity of air at that point. In the frame of\nreference of that rest postion, there is no such thing as\n"Doppler distortion" if the volume velocity there is\nlinearly related to the surface velocity of the piston. I\nthink that relationship is a constant proportionality.\n\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Bob Cain wrote:


> No, I wouldn't skewer them. I am one. Just one with a bit
> more of a technical education.
>
> The simple argument I've been using to disprove the
> phenomenon boils down to whether or not the principle of
> reciprocity applies to acoustic systems,

FWIW, I think I've found an even simpler argument that
illustrates the flaw in the vernacular argument for "Doppler
distortion" that has survived for so long. That argement
depends on the origin of the wave moving in time. It
doesn't. The origin of the wave is the rest position of the
piston. The magnitude of the wave that propegates is the
volume velocity of air at that point. In the frame of
reference of that rest postion, there is no such thing as
"Doppler distortion" if the volume velocity there is
linearly related to the surface velocity of the piston. I
think that relationship is a constant proportionality.


Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein

Franz Heymann
Aug16-04, 12:56 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\n"Bob Cain" &lt;arcane@arcanemethods.com&gt; wrote in message\nnews:cfkfio01mj2@enews3.newsguy.com...\n&gt; \n&gt;\n&gt; Norm Dresner wrote:\n&gt;\n&gt; &gt; Please don\'t skewer the "audio community at large" because of the\nbeliefs of\n&gt; &gt; a few misbegotten souls. These are generally the same folks who\nbelieve\n&gt; &gt; that speaker cables are directional (i.e. sound better\ntransmitting an AC\n&gt; &gt; waveform in one in one direction from the amplifier to the speaker\nthan in\n&gt; &gt; the other direction) because of "micro crystalline diodes" in the\nmetal in\n&gt; &gt; the wires. There is probably no limit to the number of bizarre\nbeliefs that\n&gt; &gt; these people can invent to either excuse their misbehaving\nequipment or\n&gt; &gt; justify buying something new. AFAIK sound is a longitudinal wave\n&gt; &gt; propagating in a compressible medium. (In general) It has to be\ncreated by\n&gt; &gt; some moving surface; it is originally when the sounds that they\'re\ntrying to\n&gt; &gt; reproduce are recorded.\n&gt;\n&gt; No, I wouldn\'t skewer them. I am one. Just one with a bit\n&gt; more of a technical education.\n\nBut not quite enough to get to grips with the problem.\n&gt;\n&gt; The simple argument I\'ve been using to disprove the\n&gt; phenomenon boils down to whether or not the principle of\n&gt; reciprocity applies to acoustic systems,\n\nYour simple argument is, alas, incorrect.\n\n&gt; whether the motion\n&gt; of an ideal test piston (zero mechanical impedence) in an\n&gt; infinite waveguide, a tube, with a plane wave traveling in\n&gt; it will be the same motion as that of a piston creating that\n&gt; wave but with a delay. Seems obvious to me and I think, but\n&gt; am not sure, that this reciprocity can be proved by an\n&gt; appeal to the conservation of energy.\n\nThis is essentially where you are quite wrong.\nThe radiation impedance of a piston in a tube of the same diameter is\nidentical with the acoustic impedance of a sound wave propagated in\nthe tube. Such a piston will not cause a high frequency to be\nmodulated by a low frequency vibration of the source.\n\nOn the other hand, the radiation impedance of a piston, either free or\nmounted in a baffle, is strongly frequency-dependant. In particular,\nthis results in the circumstance that the piston has to vibrate with a\nmuch larger velocity at a low frequency than at a high frequency, if\nequal sound pressures are to be produced at a large distance from the\npiston. In a freely propagating plane wave, these two velocities are\nidentical. The nett effect is that when, on this piston, a high\nfrequency vibration is superimposed on a low frequency one, it\neffectively finds itself produced by a source moving at a velocity\nlarger than that required by the superposition principle, which in\nturn will then produce a frequency-modulated output.\nThe effect is quantitatively calculable. It turns out to be\nnegligibly small for all except determined audiophiles in the case of\nspeakers operating in normal listening conditions.\n\n[snip]\n\nFranz\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"Bob Cain" <arcane@arcanemethods.com> wrote in message
news:cfkfio01mj2@enews3.newsguy.com...
>
>
> Norm Dresner wrote:
>
> > Please don't skewer the "audio community at large" because of the
beliefs of
> > a few misbegotten souls. These are generally the same folks who
believe
> > that speaker cables are directional (i.e. sound better
transmitting an AC
> > waveform in one in one direction from the amplifier to the speaker
than in
> > the other direction) because of "micro crystalline diodes" in the
metal in
> > the wires. There is probably no limit to the number of bizarre
beliefs that
> > these people can invent to either excuse their misbehaving
equipment or
> > justify buying something new. AFAIK sound is a longitudinal wave
> > propagating in a compressible medium. (In general) It has to be
created by
> > some moving surface; it is originally when the sounds that they're
trying to
> > reproduce are recorded.
>
> No, I wouldn't skewer them. I am one. Just one with a bit
> more of a technical education.

But not quite enough to get to grips with the problem.
>
> The simple argument I've been using to disprove the
> phenomenon boils down to whether or not the principle of
> reciprocity applies to acoustic systems,

Your simple argument is, alas, incorrect.

> whether the motion
> of an ideal test piston (zero mechanical impedence) in an
> infinite waveguide, a tube, with a plane wave traveling in
> it will be the same motion as that of a piston creating that
> wave but with a delay. Seems obvious to me and I think, but
> am not sure, that this reciprocity can be proved by an
> appeal to the conservation of energy.

This is essentially where you are quite wrong.
The radiation impedance of a piston in a tube of the same diameter is
identical with the acoustic impedance of a sound wave propagated in
the tube. Such a piston will not cause a high frequency to be
modulated by a low frequency vibration of the source.

On the other hand, the radiation impedance of a piston, either free or
mounted in a baffle, is strongly frequency-dependant. In particular,
this results in the circumstance that the piston has to vibrate with a
much larger velocity at a low frequency than at a high frequency, if
equal sound pressures are to be produced at a large distance from the
piston. In a freely propagating plane wave, these two velocities are
identical. The nett effect is that when, on this piston, a high
frequency vibration is superimposed on a low frequency one, it
effectively finds itself produced by a source moving at a velocity
larger than that required by the superposition principle, which in
turn will then produce a frequency-modulated output.
The effect is quantitatively calculable. It turns out to be
negligibly small for all except determined audiophiles in the case of
speakers operating in normal listening conditions.

[snip]

Franz

Bob Cain
Aug19-04, 04:50 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\nFranz Heymann wrote:\n\n&gt; "Bob Cain" &lt;arcane@arcanemethods.com&gt; wrote in message\n\n&gt;&gt;No, I wouldn\'t skewer them. I am one. Just one with a bit\n&gt;&gt;more of a technical education.\n&gt;\n&gt;\n&gt; But not quite enough to get to grips with the problem.\n\nNo argument there or I wouldn\'t be here. :-)\n\n&gt;\n&gt;&gt;The simple argument I\'ve been using to disprove the\n&gt;&gt;phenomenon boils down to whether or not the principle of\n&gt;&gt;reciprocity applies to acoustic systems,\n&gt;\n&gt;\n&gt; Your simple argument is, alas, incorrect.\n\nWould you agree that it is correct in the toy context of the\ninfinite tube?\n\n&gt;\n&gt;\n&gt;&gt;whether the motion\n&gt;&gt;of an ideal test piston (zero mechanical impedence) in an\n&gt;&gt;infinite waveguide, a tube, with a plane wave traveling in\n&gt;&gt;it will be the same motion as that of a piston creating that\n&gt;&gt;wave but with a delay. Seems obvious to me and I think, but\n&gt;&gt;am not sure, that this reciprocity can be proved by an\n&gt;&gt;appeal to the conservation of energy.\n&gt;\n&gt;\n&gt; This is essentially where you are quite wrong.\n\nOk. Even in the toy tube?\n\n&gt; The radiation impedance of a piston in a tube of the same diameter is\n&gt; identical with the acoustic impedance of a sound wave propagated in\n&gt; the tube. Such a piston will not cause a high frequency to be\n&gt; modulated by a low frequency vibration of the source.\n\nThis is what I claimed also (eventually, in the argument\nthat rages elsewhere), so I understand that much. This\ncompletely invalidates the vernacular argument that is\nusually employed to justify Doppler distortion, however,\nwhich is what I was trying to do from intuition that it was\nwrong to eventual understanding of why.\n\nMy argument was couched in terms that my opponents could\nunderstand and that came to me in that context. I said that\nunder those conditions, the velocity wave that would be\ncreated would be of the same magnitude and shape as that of\nthe piston\'s velocity and since the piston is _in_ the wave\nit is generating, it is always in the correct instantaneous\nposition for the instantaneous velocity it is imparting to\nthe wave.\n\nIs that nonsense or is it equivalent to your much simpler\nstatement? I guess your principle is hidden in the\nassumption I made that the velocity wave would be of the\nsame magnitude and shape as that of the piston. Without it\nthat wouldn\'t be true.\n\n\n&gt;\n&gt; On the other hand, the radiation impedance of a piston, either free or\n&gt; mounted in a baffle, is strongly frequency-dependant. In particular,\n&gt; this results in the circumstance that the piston has to vibrate with a\n&gt; much larger velocity at a low frequency than at a high frequency, if\n&gt; equal sound pressures are to be produced at a large distance from the\n&gt; piston. In a freely propagating plane wave, these two velocities are\n&gt; identical. The nett effect is that when, on this piston, a high\n&gt; frequency vibration is superimposed on a low frequency one, it\n&gt; effectively finds itself produced by a source moving at a velocity\n&gt; larger than that required by the superposition principle, which in\n&gt; turn will then produce a frequency-modulated output.\n&gt; The effect is quantitatively calculable. It turns out to be\n&gt; negligibly small for all except determined audiophiles in the case of\n&gt; speakers operating in normal listening conditions.\n\nOk, this is substantially different than my explanation for\nwhy, in those conditions, Doppler distortion was in\nevidence. My explanation was that Doppler distortion was\nonly in evidence when there was a difference in the coupling\nof the piston to the air as a function of frequency, that is\nwhen the pressure in the far field was a frequency dependant\nfunction of the velocity of the piston. I think that is\nequivalent, if using less appropriate and less exact\nterminology, correct?\n\n\nMany Thanks,\n\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Franz Heymann wrote:

> "Bob Cain" <arcane@arcanemethods.com> wrote in message

>>No, I wouldn't skewer them. I am one. Just one with a bit
>>more of a technical education.
>
>
> But not quite enough to get to grips with the problem.

No argument there or I wouldn't be here. :-)

>
>>The simple argument I've been using to disprove the
>>phenomenon boils down to whether or not the principle of
>>reciprocity applies to acoustic systems,
>
>
> Your simple argument is, alas, incorrect.

Would you agree that it is correct in the toy context of the
infinite tube?

>
>
>>whether the motion
>>of an ideal test piston (zero mechanical impedence) in an
>>infinite waveguide, a tube, with a plane wave traveling in
>>it will be the same motion as that of a piston creating that
>>wave but with a delay. Seems obvious to me and I think, but
>>am not sure, that this reciprocity can be proved by an
>>appeal to the conservation of energy.
>
>
> This is essentially where you are quite wrong.

Ok. Even in the toy tube?

> The radiation impedance of a piston in a tube of the same diameter is
> identical with the acoustic impedance of a sound wave propagated in
> the tube. Such a piston will not cause a high frequency to be
> modulated by a low frequency vibration of the source.

This is what I claimed also (eventually, in the argument
that rages elsewhere), so I understand that much. This
completely invalidates the vernacular argument that is
usually employed to justify Doppler distortion, however,
which is what I was trying to do from intuition that it was
wrong to eventual understanding of why.

My argument was couched in terms that my opponents could
understand and that came to me in that context. I said that
under those conditions, the velocity wave that would be
created would be of the same magnitude and shape as that of
the piston's velocity and since the piston is _in_ the wave
it is generating, it is always in the correct instantaneous
position for the instantaneous velocity it is imparting to
the wave.

Is that nonsense or is it equivalent to your much simpler
statement? I guess your principle is hidden in the
assumption I made that the velocity wave would be of the
same magnitude and shape as that of the piston. Without it
that wouldn't be true.


>
> On the other hand, the radiation impedance of a piston, either free or
> mounted in a baffle, is strongly frequency-dependant. In particular,
> this results in the circumstance that the piston has to vibrate with a
> much larger velocity at a low frequency than at a high frequency, if
> equal sound pressures are to be produced at a large distance from the
> piston. In a freely propagating plane wave, these two velocities are
> identical. The nett effect is that when, on this piston, a high
> frequency vibration is superimposed on a low frequency one, it
> effectively finds itself produced by a source moving at a velocity
> larger than that required by the superposition principle, which in
> turn will then produce a frequency-modulated output.
> The effect is quantitatively calculable. It turns out to be
> negligibly small for all except determined audiophiles in the case of
> speakers operating in normal listening conditions.

Ok, this is substantially different than my explanation for
why, in those conditions, Doppler distortion was in
evidence. My explanation was that Doppler distortion was
only in evidence when there was a difference in the coupling
of the piston to the air as a function of frequency, that is
when the pressure in the far field was a frequency dependant
function of the velocity of the piston. I think that is
equivalent, if using less appropriate and less exact
terminology, correct?


Many Thanks,


Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein

Bob Cain
Aug31-04, 03:55 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\nFranz, sorry it took so darned long to get back to this but\na lot of thinking and arguing about it elsewhere has been\nnecessasary for me since you posted it.\n\nFranz Heymann wrote:\n\n\n&gt;&gt;whether the motion\n&gt;&gt;of an ideal test piston (zero mechanical impedence) in an\n&gt;&gt;infinite waveguide, a tube, with a plane wave traveling in\n&gt;&gt;it will be the same motion as that of a piston creating that\n&gt;&gt;wave but with a delay. Seems obvious to me and I think, but\n&gt;&gt;am not sure, that this reciprocity can be proved by an\n&gt;&gt;appeal to the conservation of energy.\n&gt;\n&gt;\n&gt; This is essentially where you are quite wrong.\n&gt; The radiation impedance of a piston in a tube of the same diameter is\n&gt; identical with the acoustic impedance of a sound wave propagated in\n&gt; the tube. Such a piston will not cause a high frequency to be\n&gt; modulated by a low frequency vibration of the source.\n\nNot sure why it makes me wrong because I think it\'s exactly\nwhat I was trying to say. Clarity of expression is\nsomething I\'ve not often been accused of, however.\nReciprocity is a consequence of what you are saying. I\njumped to that consequence without the intermediate\nreasoning that was necessasary. I just couldn\'t find any\nreason why reciprocity wouldn\'t apply (and a time reversal\nargument seemed to nail it, but only for me.)\n\n&gt;\n&gt; On the other hand, the radiation impedance of a piston, either free or\n&gt; mounted in a baffle, is strongly frequency-dependant.\n\nAnd it thus follows that any and all Doppler mixing that\noccurs between Tx and Rx in a wave mechanical system is due\nto frequency dependant coupling. This was an epiphany that\nfor me explains all the examples people have put up in the\nacoustics discussion on this topic (including the case of a\npiston in a tube of which I\'ve been able to convince no\none.) So far over there I\'m the only one that believes it\nbut, whatever.\n\nThe guys that claim to be "experts" in acoustics on\nalt.sci.physics.acoustics are a terribly hard sell on this\none. They really believe, and won\'t be disuaded, that the\nvelocity of the piston at the piston-gas interface is not\nonly imparted to the gas but that it "Doppler distorts" it\nat the same time. They simply cannot be talked out of this\ndouble accounting and have come up with all kinds of\nformulaic expressions for it that in the end contain\nundefined constants that give them no predictive power at\nall. For the most part, they just write down an equation\nand say, "it must be of this form."\n\nThe latest stone I\'ve lobbed toward the piston-in-a-tube\ndebate comes from:\n\nhttp://www.silcom.com/~aludwig/Physics/Piston_collisions.htm\n\nwhich simply states that in a tube a step function in the\nvelocity of the piston results in a step velocity wave\npropegating from the piston with the same magnitude as the\npiston\'s. With this as an axiom and a little Fourier theory\nI think it will be possible to easily prove that a piston in\na tube perfectly transcribes it\'s motion onto the wave that\npropegates away from it. This all presumes operation in the\nlinear regime of air, of course.\n\nDo you know if a general, predictive theory of the effect\nhas been developed based on the principle that you state?\nLooks like it could be a rather hairy field theory, way\nbeyond my meager mathematical talents.\n\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Franz, sorry it took so darned long to get back to this but
a lot of thinking and arguing about it elsewhere has been
necessasary for me since you posted it.

Franz Heymann wrote:


>>whether the motion
>>of an ideal test piston (zero mechanical impedence) in an
>>infinite waveguide, a tube, with a plane wave traveling in
>>it will be the same motion as that of a piston creating that
>>wave but with a delay. Seems obvious to me and I think, but
>>am not sure, that this reciprocity can be proved by an
>>appeal to the conservation of energy.
>
>
> This is essentially where you are quite wrong.
> The radiation impedance of a piston in a tube of the same diameter is
> identical with the acoustic impedance of a sound wave propagated in
> the tube. Such a piston will not cause a high frequency to be
> modulated by a low frequency vibration of the source.

Not sure why it makes me wrong because I think it's exactly
what I was trying to say. Clarity of expression is
something I've not often been accused of, however.
Reciprocity is a consequence of what you are saying. I
jumped to that consequence without the intermediate
reasoning that was necessasary. I just couldn't find any
reason why reciprocity wouldn't apply (and a time reversal
argument seemed to nail it, but only for me.)

>
> On the other hand, the radiation impedance of a piston, either free or
> mounted in a baffle, is strongly frequency-dependant.

And it thus follows that any and all Doppler mixing that
occurs between Tx and Rx in a wave mechanical system is due
to frequency dependant coupling. This was an epiphany that
for me explains all the examples people have put up in the
acoustics discussion on this topic (including the case of a
piston in a tube of which I've been able to convince no
one.) So far over there I'm the only one that believes it
but, whatever.

The guys that claim to be "experts" in acoustics on
alt.sci.physics.acoustics are a terribly hard sell on this
one. They really believe, and won't be disuaded, that the
velocity of the piston at the piston-gas interface is not
only imparted to the gas but that it "Doppler distorts" it
at the same time. They simply cannot be talked out of this
double accounting and have come up with all kinds of
formulaic expressions for it that in the end contain
undefined constants that give them no predictive power at
all. For the most part, they just write down an equation
and say, "it must be of this form."

The latest stone I've lobbed toward the piston-in-a-tube
debate comes from:

http://www.silcom.com/~aludwig/Physics/Piston_collisions.htm

which simply states that in a tube a step function in the
velocity of the piston results in a step velocity wave
propegating from the piston with the same magnitude as the
piston's. With this as an axiom and a little Fourier theory
I think it will be possible to easily prove that a piston in
a tube perfectly transcribes it's motion onto the wave that
propegates away from it. This all presumes operation in the
linear regime of air, of course.

Do you know if a general, predictive theory of the effect
has been developed based on the principle that you state?
Looks like it could be a rather hairy field theory, way
beyond my meager mathematical talents.


Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein

Franz Heymann
Sep1-04, 03:22 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>"Bob Cain" &lt;arcane@arcanemethods.com&gt; wrote in message\nnews:ch15v801k2h@enews1.newsguy.com...\n&gt; \n&gt;\n&gt; Franz, sorry it took so darned long to get back to this but\n&gt; a lot of thinking and arguing about it elsewhere has been\n&gt; necessasary for me since you posted it.\n&gt;\n&gt; Franz Heymann wrote:\n&gt;\n&gt;\n&gt; &gt;&gt;whether the motion\n&gt; &gt;&gt;of an ideal test piston (zero mechanical impedence) in an\n&gt; &gt;&gt;infinite waveguide, a tube, with a plane wave traveling in\n&gt; &gt;&gt;it will be the same motion as that of a piston creating that\n&gt; &gt;&gt;wave but with a delay. Seems obvious to me and I think, but\n&gt; &gt;&gt;am not sure, that this reciprocity can be proved by an\n&gt; &gt;&gt;appeal to the conservation of energy.\n&gt; &gt;\n&gt; &gt;\n&gt; &gt; This is essentially where you are quite wrong.\n&gt; &gt; The radiation impedance of a piston in a tube of the same diameter\nis\n&gt; &gt; identical with the acoustic impedance of a sound wave propagated\nin\n&gt; &gt; the tube. Such a piston will not cause a high frequency to be\n&gt; &gt; modulated by a low frequency vibration of the source.\n&gt;\n&gt; Not sure why it makes me wrong because I think it\'s exactly\n&gt; what I was trying to say. Clarity of expression is\n&gt; something I\'ve not often been accused of, however.\n&gt; Reciprocity is a consequence of what you are saying. I\n&gt; jumped to that consequence without the intermediate\n&gt; reasoning that was necessasary. I just couldn\'t find any\n&gt; reason why reciprocity wouldn\'t apply (and a time reversal\n&gt; argument seemed to nail it, but only for me.)\n&gt;\n&gt; &gt;\n&gt; &gt; On the other hand, the radiation impedance of a piston, either\nfree or\n&gt; &gt; mounted in a baffle, is strongly frequency-dependant.\n&gt;\n&gt; And it thus follows that any and all Doppler mixing that\n&gt; occurs between Tx and Rx in a wave mechanical system is due\n&gt; to frequency dependant coupling. This was an epiphany that\n&gt; for me explains all the examples people have put up in the\n&gt; acoustics discussion on this topic (including the case of a\n&gt; piston in a tube of which I\'ve been able to convince no\n&gt; one.) So far over there I\'m the only one that believes it\n&gt; but, whatever.\n&gt;\n&gt; The guys that claim to be "experts" in acoustics on\n&gt; alt.sci.physics.acoustics are a terribly hard sell on this\n&gt; one. They really believe, and won\'t be disuaded, that the\n&gt; velocity of the piston at the piston-gas interface is not\n&gt; only imparted to the gas but that it "Doppler distorts" it\n&gt; at the same time. They simply cannot be talked out of this\n&gt; double accounting and have come up with all kinds of\n&gt; formulaic expressions for it that in the end contain\n&gt; undefined constants that give them no predictive power at\n&gt; all. For the most part, they just write down an equation\n&gt; and say, "it must be of this form."\n&gt;\n&gt; The latest stone I\'ve lobbed toward the piston-in-a-tube\n&gt; debate comes from:\n&gt;\n&gt; http://www.silcom.com/~aludwig/Physics/Piston_collisions.htm\n&gt;\n&gt; which simply states that in a tube a step function in the\n&gt; velocity of the piston results in a step velocity wave\n&gt; propegating from the piston with the same magnitude as the\n&gt; piston\'s. With this as an axiom and a little Fourier theory\n&gt; I think it will be possible to easily prove that a piston in\n&gt; a tube perfectly transcribes it\'s motion onto the wave that\n&gt; propegates away from it. This all presumes operation in the\n&gt; linear regime of air, of course.\n&gt;\n&gt; Do you know if a general, predictive theory of the effect\n&gt; has been developed based on the principle that you state?\n&gt; Looks like it could be a rather hairy field theory, way\n&gt; beyond my meager mathematical talents.\n\nBob, at 80 years of age, 100 miles from the nearest University library\nand on the brink of my second childhood, I can regrettably only\ncomment in qualitative terms on things I lectured on more than 50\nyears ago.\n\nI should be surprised if Morse did not go into the quantitative\ndetails of Doppler distortion in a vibrating piston radiating into\nfree space. What I do know for certain is that you are right. A\npiston in a tube, with the same area as the cross section of the tube\ndoes not produce Doppler distortion. This is proven quite simply by\ninserting a massless piston halfway along the tube and exciting a wave\nfrom the left hand end of the tube. The sound propagating to the\nright of the piston will be independent of whether the piston id there\nor not. The case of a piston in either a flat baffle or in free\nspace is totally different and will produce Doppler distortion, as I\nhave explained. I did add, and say so again, the efect is almost\nnegligibly small, since the peak velocity of the piston will always be\ntiny compared to the speed of sound.\n\nFranz\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"Bob Cain" <arcane@arcanemethods.com> wrote in message
news:ch15v801k2h@enews1.newsguy.com...
>
>
> Franz, sorry it took so darned long to get back to this but
> a lot of thinking and arguing about it elsewhere has been
> necessasary for me since you posted it.
>
> Franz Heymann wrote:
>
>
> >>whether the motion
> >>of an ideal test piston (zero mechanical impedence) in an
> >>infinite waveguide, a tube, with a plane wave traveling in
> >>it will be the same motion as that of a piston creating that
> >>wave but with a delay. Seems obvious to me and I think, but
> >>am not sure, that this reciprocity can be proved by an
> >>appeal to the conservation of energy.
> >
> >
> > This is essentially where you are quite wrong.
> > The radiation impedance of a piston in a tube of the same diameter
is
> > identical with the acoustic impedance of a sound wave propagated
in
> > the tube. Such a piston will not cause a high frequency to be
> > modulated by a low frequency vibration of the source.
>
> Not sure why it makes me wrong because I think it's exactly
> what I was trying to say. Clarity of expression is
> something I've not often been accused of, however.
> Reciprocity is a consequence of what you are saying. I
> jumped to that consequence without the intermediate
> reasoning that was necessasary. I just couldn't find any
> reason why reciprocity wouldn't apply (and a time reversal
> argument seemed to nail it, but only for me.)
>
> >
> > On the other hand, the radiation impedance of a piston, either
free or
> > mounted in a baffle, is strongly frequency-dependant.
>
> And it thus follows that any and all Doppler mixing that
> occurs between Tx and Rx in a wave mechanical system is due
> to frequency dependant coupling. This was an epiphany that
> for me explains all the examples people have put up in the
> acoustics discussion on this topic (including the case of a
> piston in a tube of which I've been able to convince no
> one.) So far over there I'm the only one that believes it
> but, whatever.
>
> The guys that claim to be "experts" in acoustics on
> alt.sci.physics.acoustics are a terribly hard sell on this
> one. They really believe, and won't be disuaded, that the
> velocity of the piston at the piston-gas interface is not
> only imparted to the gas but that it "Doppler distorts" it
> at the same time. They simply cannot be talked out of this
> double accounting and have come up with all kinds of
> formulaic expressions for it that in the end contain
> undefined constants that give them no predictive power at
> all. For the most part, they just write down an equation
> and say, "it must be of this form."
>
> The latest stone I've lobbed toward the piston-in-a-tube
> debate comes from:
>
> http://www.silcom.com/~aludwig/Physics/Piston_collisions.htm
>
> which simply states that in a tube a step function in the
> velocity of the piston results in a step velocity wave
> propegating from the piston with the same magnitude as the
> piston's. With this as an axiom and a little Fourier theory
> I think it will be possible to easily prove that a piston in
> a tube perfectly transcribes it's motion onto the wave that
> propegates away from it. This all presumes operation in the
> linear regime of air, of course.
>
> Do you know if a general, predictive theory of the effect
> has been developed based on the principle that you state?
> Looks like it could be a rather hairy field theory, way
> beyond my meager mathematical talents.

Bob, at 80 years of age, 100 miles from the nearest University library
and on the brink of my second childhood, I can regrettably only
comment in qualitative terms on things I lectured on more than 50
years ago.

I should be surprised if Morse did not go into the quantitative
details of Doppler distortion in a vibrating piston radiating into
free space. What I do know for certain is that you are right. A
piston in a tube, with the same area as the cross section of the tube
does not produce Doppler distortion. This is proven quite simply by
inserting a massless piston halfway along the tube and exciting a wave
from the left hand end of the tube. The sound propagating to the
right of the piston will be independent of whether the piston id there
or not. The case of a piston in either a flat baffle or in free
space is totally different and will produce Doppler distortion, as I
have explained. I did add, and say so again, the efect is almost
negligibly small, since the peak velocity of the piston will always be
tiny compared to the speed of sound.

Franz

Bob Cain
Sep21-04, 03:30 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n\n\nFranz Heymann wrote:\n\n&gt; I should be surprised if Morse did not go into the quantitative\n&gt; details of Doppler distortion in a vibrating piston radiating into\n&gt; free space.\n\nMorse? Did I miss a reference I shouldn\'t have?\n\n&gt; What I do know for certain is that you are right. A\n&gt; piston in a tube, with the same area as the cross section of the tube\n&gt; does not produce Doppler distortion. This is proven quite simply by\n&gt; inserting a massless piston halfway along the tube and exciting a wave\n&gt; from the left hand end of the tube.\n\nThe question has now come down to what the particle velocity\nis about its quiescent position is as a function of the\nplane wave\'s velocity function of time at that position. If\nit\'s the same then a proof that there\'s no Doppler type\nmixing in a tube is easy but I\'ll be damned if I can derive\nwhat that function is.\n\n\nThanks,\n\nBob\n--\n\n"Things should be described as simply as possible, but no\nsimpler."\n\nA. Einstein\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Franz Heymann wrote:

> I should be surprised if Morse did not go into the quantitative
> details of Doppler distortion in a vibrating piston radiating into
> free space.

Morse? Did I miss a reference I shouldn't have?

> What I do know for certain is that you are right. A
> piston in a tube, with the same area as the cross section of the tube
> does not produce Doppler distortion. This is proven quite simply by
> inserting a massless piston halfway along the tube and exciting a wave
> from the left hand end of the tube.

The question has now come down to what the particle velocity
is about its quiescent position is as a function of the
plane wave's velocity function of time at that position. If
it's the same then a proof that there's no Doppler type
mixing in a tube is easy but I'll be damned if I can derive
what that function is.


Thanks,

Bob
--

"Things should be described as simply as possible, but no
simpler."

A. Einstein