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|<ings
Apr24-10, 05:10 PM
This is just to see if I remember? Please confirm, correct any errors, and answer the questions (q's in bold)

1. The problem statement, all variables and given/known data

What geometric transformations will "transform"
f(t) = et \stackrel{transformations}{\rightarrow} \frac{mg}{b} * (1 - e-bt/m)?

2. Relevant equations

f(t) = \frac{mg}{b} * (1 - e-bt/m)

= \frac{mg}{b} - \frac{mg}{b})e-bt/m

3. The attempt at a solution

(1) vertical scaling? or horizontal?
f((-b/m)t) -> e-bt/m
let the new f function be equal to g, another function
i.e. g(t) = e-bt/m

(2) reflection across the x-axis, right?
-1 * g(t) = -e-bt/m
let the new g function be equal to h, another function
i.e. h(t) = -e-bt/m

(3) i think this one is the vertical scaling.
\frac{mg}{b} * h(t) = -\frac{mg}{b}e-bt/m
let the new h function be equal to i, another function
i.e. i(t) = -\frac{mg}{b}e-bt/m

(4) vertical translation
i(t) + \frac{mg}{b} = \frac{mg}{b} - \frac{mg}{b}e-bt/m

= \frac{mg}{b} * (1 - e-bt/m)

= f(t)

also, is the reflection across the y-axis done by multiplying by -1 inside of the done like this?: f(x) \stackrel{reflection across y-axis}{\rightarrow} f(-x). TNX