Sig Figs: Solve Mixed Equations and Get the Correct Answer

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    Significant digits
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Discussion Overview

The discussion revolves around the application of significant figures in mixed equations within the context of General Chemistry. Participants explore how to correctly calculate and round answers while considering the rules of significant figures.

Discussion Character

  • Homework-related
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant requests help with significant figures in a mixed equation, expressing confusion over the rules to apply.
  • Another suggests using a basic calculator and rounding the answer to 7 digits, though the reasoning behind this is unclear.
  • A participant questions how to arrive at 7 digits, proposing that the most significant contribution comes from a specific term and suggesting truncation based on uncertainty.
  • Another participant asserts that the final result should match the number of significant digits of the least accurate measurement in the calculation.
  • One participant expresses frustration and confusion regarding the differing interpretations of significant figures.
  • A participant provides a detailed breakdown of the calculations, applying rules for significant figures to each term in the equation.
  • Another participant shares their experience of disagreement with a professor regarding the reporting of significant figures, highlighting the need for clarity in indicating precision.
  • One participant notes the importance of displaying a trailing decimal point to signify the correct number of significant figures.

Areas of Agreement / Disagreement

Participants express differing views on how to apply the rules of significant figures, with no consensus reached on the correct approach or final answer. Some participants agree on the importance of the least accurate measurement affecting the final result, while others present conflicting interpretations.

Contextual Notes

Participants reference specific rules for significant figures but do not fully resolve the mathematical steps involved in the calculations, leading to varying interpretations of the final answer.

Baby Einstein
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Please, if someone helps, I will forever be in your debt!

Just Gen Chem I...but its about Sig Figs...know one seems to know the rules about which law to use when you have mixed equations

0.0001235 X 0.0012 + ( 5.48 - 0.004) X 9.1 + (8.2 x10 raised to the neg 6)

Give the correct answer with the correct number of sinigacant figures.
 
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Just use a basic calculator. Once you've done that, your answer should only have only 7 digits. If it has more, round your smallest in value number until you reach 7 digits.

Paden Roder
 
How do you get 7 digits?? Assuming uncertainty in the last digit of all given numbers, the most significant contribution comes from the term ( 5.48 - 0.004) X 9.1 - the uncertainty is on the order of 0.01*9.1 + 0.1*5.48 = roughly 0.5
So I would truncate the answer to the first digit past the decimal point... the terms with 10-6 and 0.000.. x 0.00... are 100% negligible.
 
Round your answer off to the same number of significant digits as the element in your calculation that contains the fewest significant digits.
 
:bugeye: Now I'm really confused
 
Your final numerical result cannot be more accurate than the least accurate of the items that go into your calculation.
 
Oh well, Iv'e got some type of block...to hell with this question.
 
[tex]0.001235X0.0012=1.5X10^{-7}[/tex] : 2 significant figures to follow the least one which is 0.0012 which has 2 significant figures.(Rule #1)

[tex](5.48-0.004)=5.476 = 5.48[/tex] : 2 decimal places because the rest of the decimal places has no meaning since 5.48 has 2 decimal places only.(Rule #2)

5.48X9.1=50 ( 2 significant figures : Rule #1)

So,
[tex]1.5X10^{-7} + 50 + 8.2X10^{-6} = 50[/tex] ( 2 significant figures : Rule #2)
 
Thats what I thought 49.6540082 reported to two digits = 50, but my prof. says I'm wrong!
 
  • #10
Baby Einstein said:
Thats what I thought 49.6540082 reported to two digits = 50, but my prof. says I'm wrong!
I hate teachers like that. I've had to correct my teacher on how an electrical current works... he was completely backwards on parrallel/linear currents.
 
  • #11
Baby Einstein said:
Thats what I thought 49.6540082 reported to two digits = 50, but my prof. says I'm wrong!

Technically, your prof is correct. You need to display the trailing decimal point to indicate that you really do have two significant figures. Without it you are indicating the result is an integer which is "infinitely precise." Mathematically they are the same but the distinction is there when calculations involve measurements.
 
  • #12
Thanks a lot guys. :approve:
 

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