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arivero
Sep9-04, 03:02 PM
A particle in a gravitational circular orbit around a mass M fullfills, for generical space time dimension D:

c^2 R^(5-D) Lp^(D-2) = LM I^2

being I= 1/2 R x V, V the speed of the particle,
Lp the Planck Length, and LM the Comptom Length of M.

I wonder if someone has been this very easy (Newtonian!) relationship in any textbook or article, and/or exploited
it to single out sort of critical or special dimensions.

D=2 is simply the fact that in a line the density of force lines keeps constant, so forces do not depend of distance.

D>5 or D<5 can be used to register different regimes for constant angular momenta. But there one should break the balance of D=5 by introducing general relativity or variants.

The most interesting trick comes if one quantises "I" in units of Planck Length. So we have, if I=n Lp (note now the natural units, c=h=1):

R^(5-D) Lp^(D-4) = LM n^2

And we have that for D=4, the only dependence on gravity hides in the quantisation! Any use for this?

I am specially interested on bibliographical references to this family of arguments because I did a very short note in this line
http://dftuz.unizar.es/~rivero/research/simple.pdf
and I would like to be able to see if I should upload something similar in gr-qc.

Bernd Binder
Oct3-04, 03:49 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\nDear Alejandro,\n\n"arivero" &lt;arivero@posta.unizar.es&gt; wrote in\nnews:arivero.1c8a8h@physicsforums.com...\n&gt; A particle in a gravitational circular orbit around a mass M fullfills,\n&gt; for generical space time dimension D:\n&gt;\n&gt; c^2 R^(5-D) Lp^(D-2) = LM I^2\n&gt;\n&gt; being I= 1/2 R x V, V the speed of the particle,\n&gt; Lp the Planck Length, and LM the Comptom Length of M.\n&gt;\n&gt; I wonder if someone has been this very easy (Newtonian!) relationship\n&gt; in any textbook or article, and/or exploited\n&gt; it to single out sort of critical or special dimensions.\n&gt;\n&gt; D=2 is simply the fact that in a line the density of force lines keeps\n&gt; constant, so forces do not depend of distance.\n&gt;\n&gt; D&gt;5 or D&lt;5 can be used to register different regimes for constant\n&gt; angular momenta. But there one should break the balance of D=5 by\n&gt; introducing general relativity or variants.\n&gt;\n&gt; The most interesting trick comes if one quantises "I" in units of\n&gt; Planck Length. So we have, if I=n Lp (note now the natural units,\n&gt; c=h=1):\n&gt;\n&gt; R^(5-D) Lp^(D-4) = LM n^2\n&gt;\n\nhave you noticed that this equation is absolutely independent of setting\nc=h=1 ?\nJust insert\n\nI=n cLp\n\ninto your first equation.\n\nI would say, that a choice c=h=1 could prevent you from going further.\nWith\n\nLp = h/Mpc\n\nwhere Mp is the Planck mass, we have\nIMp = n h\n\nIn this quantum relation the purely geometric part I contains the same SI\nspace/time units (meter, second) like h, so I/h does not dependent on the\nchoice of SI geometric units and means that Mp is proportional to n. If the\nmass Mp can be divided by n, Mp/n could be more fundamental than Mp.\n\nWhere could n come from? Generally, with Mp = h/Lpc and the choice M0 = Mp\nn^(D-3)\n\nR0^(5-D) Lp^(D-4) = n^2 h/M0c = n^(5-D) h/Mpc\n\nwe have a fundamental length\n\nR0= n Lp\n\nassuming that I = cR0 is fundamental quantum. Consequently, M0 could be more\nfundamental than Mp. With\n\nIM0 = n^(D-2) h\n\nin a compactified D=2 geometry, both, M0 = Mp/n and I would be as\nfundamental as h.\n\nCould there be a special n with a physical meaning?\nTransforming\n\nn^2 = hc/(GM0^2)\n\ninto a Newton type relation\n\nn^2 G M0^2/R = hc/R\n\nwe could find a clear interpretation:\nn^2 M0-masses interacting gravitationally would reach the electromagnetic\ncoupling of about 137 charges at any distance R.\n\nWith the Planck mass\nhttp://scienceworld.wolfram.com/physics/PlanckMass.html\nand taking M0 as the proton mass we get i.e.\n\nn ~ 3*10^19\nn^2 ~ 9*10^38\n\nI expect, that c^2 R^(5-D) Lp^(D-2) = LM I^2 is correct, that I is a\nquantum, and that n can be found from a pure geometrical (Gaussian)\napproach relating different kind of topologies.\n\nRegards,\nBernd\n\n\n\n&gt; I am specially interested on bibliographical references to this family\n&gt; of arguments because I did a very short note in this line\n&gt; http://dftuz.unizar.es/~rivero/research/simple.pdf\n&gt; and I would like to be able to see if I should upload something similar\n&gt; in gr-qc.\n&gt;\n&gt;\n&gt;\n&gt; Univ Zaragoza, PhD\nScience---------------------------------------------------------------------\n---\n&gt; This post submitted through the LaTeX-enabled physicsforums.com\n&gt; To view this post with LaTeX images:\n&gt; http://www.physicsforums.com/showthread.php?t=41844#post304135\n&gt;\n\n\n\n\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Dear Alejandro,

"arivero" <arivero@posta.unizar.es> wrote in
news:arivero.1c8a8h@physicsforums.com...
> A particle in a gravitational circular orbit around a mass M fullfills,
> for generical space time dimension D:
>
> c^2 R^(5-D) Lp^(D-2) = LM I^2
>
> being I= 1/2 R x V, V the speed of the particle,
> Lp the Planck Length, and LM the Comptom Length of M.
>
> I wonder if someone has been this very easy (Newtonian!) relationship
> in any textbook or article, and/or exploited
> it to single out sort of critical or special dimensions.
>
> D=2 is simply the fact that in a line the density of force lines keeps
> constant, so forces do not depend of distance.
>
> D>5 or D<5 can be used to register different regimes for constant
> angular momenta. But there one should break the balance of D=5 by
> introducing general relativity or variants.
>
> The most interesting trick comes if one quantises "I" in units of
> Planck Length. So we have, if I=n Lp (note now the natural units,
> c=h=1):
>
> R^(5-D) Lp^(D-4) = LM n^2
>

have you noticed that this equation is absolutely independent of setting
c=h=1 ?
Just insert

I=n cLp

into your first equation.

I would say, that a choice c=h=1 could prevent you from going further.
With

Lp = h/Mpc

where Mp is the Planck mass, we have
IMp = n h

In this quantum relation the purely geometric part I contains the same SI
space/time units (meter, second) like h, so I/h does not dependent on the
choice of SI geometric units and means that Mp is proportional to n. If the
mass Mp can be divided by n, Mp/n could be more fundamental than Mp.

Where could n come from? Generally, with Mp = h/Lpc and the choice M0 = Mpn^(D-3)R0^(5-D) Lp^(D-4) = n^2 h/M0c = n^(5-D) h/Mpc

we have a fundamental length

R0= n Lp

assuming that I = cR0 is fundamental quantum. Consequently, M0 could be more
fundamental than Mp. With

IM0 = n^(D-2) h

in a compactified D=2 geometry, both, M0 = Mp/n and I would be as
fundamental as h.

Could there be a special n with a physical meaning?
Transforming

n^2 = hc/(GM0^2)

into a Newton type relation

n^2 G M0^2/R = hc/R

we could find a clear interpretation:
n^2 M0-masses interacting gravitationally would reach the electromagnetic
coupling of about 137 charges at any distance R.

With the Planck mass
http://scienceworld.wolfram.com/physics/PlanckMass.html
and taking M0 as the proton mass we get i.e.n ~ 3*10^19n^2 ~ 9*10^38

I expect, that c^2 R^(5-D) Lp^(D-2) = LM I^2 is correct, that I is a
quantum, and that n can be found from a pure geometrical (Gaussian)
approach relating different kind of topologies.

Regards,
Bernd



> I am specially interested on bibliographical references to this family
> of arguments because I did a very short note in this line
> http://dftuz.unizar.es/~rivero/research/simple.pdf
> and I would like to be able to see if I should upload something similar
> in gr-qc.
>
>
>
> Univ Zaragoza, PhD
Science---------------------------------------------------------------------
---
> This post submitted through the LaTeX-enabled physicsforums.com
> To view this post with LaTeX images:
> http://www.physicsforums.com/showthread.php?t=41844#post304135
>

Bernd Binder
Oct4-04, 12:22 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\nI &lt;binder@quanics.com&gt; wrote in\nnews:cjk27d\\$418\\$1@ngspool-d02.news.aol.com...\n&gt;\n&gt; Dear Alejandro,\n&gt;\n&gt; "arivero" &lt;arivero@posta.unizar.es&gt; wrote in\n&gt; news:arivero.1c8a8h@physicsforums.com...\n&gt; &gt; A particle in a gravitational circular orbit around a mass M fullfills,\n&gt; &gt; for generical space time dimension D:\n&gt; &gt;\n&gt; &gt; c^2 R^(5-D) Lp^(D-2) = LM I^2\n&gt; &gt;\n&gt; &gt; being I= 1/2 R x V, V the speed of the particle,\n&gt; &gt; Lp the Planck Length, and LM the Comptom Length of M.\n&gt; &gt;\n&gt; &gt; I wonder if someone has been this very easy (Newtonian!) relationship\n&gt; &gt; in any textbook or article, and/or exploited\n&gt; &gt; it to single out sort of critical or special dimensions.\n&gt; &gt;\n&gt; &gt; D=2 is simply the fact that in a line the density of force lines keeps\n&gt; &gt; constant, so forces do not depend of distance.\n&gt; &gt;\n&gt; &gt; D&gt;5 or D&lt;5 can be used to register different regimes for constant\n&gt; &gt; angular momenta. But there one should break the balance of D=5 by\n&gt; &gt; introducing general relativity or variants.\n&gt; &gt;\n&gt; &gt; The most interesting trick comes if one quantises "I" in units of\n&gt; &gt; Planck Length. So we have, if I=n Lp (note now the natural units,\n&gt; &gt; c=h=1):\n&gt; &gt;\n&gt; &gt; R^(5-D) Lp^(D-4) = LM n^2\n&gt; &gt;\n&gt;\n&gt; have you noticed that this equation is absolutely independent of setting\n&gt; c=h=1 ?\n&gt; Just insert\n&gt;\n&gt; I=n cLp\n&gt;\n&gt; into your first equation.\n&gt;\n&gt; I would say, that a choice c=h=1 could prevent you from going further.\n&gt; With\n&gt;\n&gt; Lp = h/Mpc\n&gt;\n&gt; where Mp is the Planck mass, we have\n&gt; IMp = n h\n&gt;\n&gt; In this quantum relation the purely geometric part I contains the same SI\n&gt; space/time units (meter, second) like h, so I/h does not dependent on the\n&gt; choice of SI geometric units and means that Mp is proportional to n. If\nthe\n&gt; mass Mp can be divided by n, Mp/n could be more fundamental than Mp.\n&gt;\n&gt; Where could n come from? Generally, with Mp = h/Lpc and the choice M0 = Mp\n&gt; n^(D-3)\n&gt;\n&gt; R0^(5-D) Lp^(D-4) = n^2 h/M0c = n^(5-D) h/Mpc\n&gt;\n&gt; we have a fundamental length\n&gt;\n&gt; R0= n Lp\n&gt;\n&gt; assuming that I = cR0 is fundamental quantum. Consequently, M0 could be\nmore\n&gt; fundamental than Mp.\n\n[...]\n\nSorry, just forgot to say:\n\n&gt;From M0(D) = Mp n^(D-3) the mass transformation introduced by varying D\n\nM0(4) = n^2 M0(2)\n\ncould provide for a 4D mass value M0(4) strong enough to create a quantum\nblack hole with a horizon near R0. Simply because\n\nG M0(4) = h c / M0(2) = c I = c^2R0\n\nThis would be a kind of topological self-consistency. With a simple\nSchwartzschild approach, the lighter and lower-dimensional compactified\nM0(2) could fit to something like a photon sphere/bubble of a black hole (up\nto some numbers, incorporating relativistic corrections should -as far as I\nremember- provide for a factor of 3, and 2\\pi for the angular dimension).\nSo n^2 could be assigned not only to topological difference between forces,\nbut also to a quantum black hole property.\n\n[...]\n\nRegards,\nBernd\n\n[...]\n\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>I <binder@quanics.com> wrote in
news:cjk27d$418$1@ngspool-d02.news.aol.com...
>
> Dear Alejandro,
>
> "arivero" <arivero@posta.unizar.es> wrote in
> news:arivero.1c8a8h@physicsforums.com...
> > A particle in a gravitational circular orbit around a mass M fullfills,
> > for generical space time dimension D:
> >
> > c^2 R^(5-D) Lp^(D-2) = LM I^2
> >
> > being I= 1/2 R x V, V the speed of the particle,
> > Lp the Planck Length, and LM the Comptom Length of M.
> >
> > I wonder if someone has been this very easy (Newtonian!) relationship
> > in any textbook or article, and/or exploited
> > it to single out sort of critical or special dimensions.
> >
> > D=2 is simply the fact that in a line the density of force lines keeps
> > constant, so forces do not depend of distance.
> >
> > D>5 or D<5 can be used to register different regimes for constant
> > angular momenta. But there one should break the balance of D=5 by
> > introducing general relativity or variants.
> >
> > The most interesting trick comes if one quantises "I" in units of
> > Planck Length. So we have, if I=n Lp (note now the natural units,
> > c=h=1):
> >
> > R^(5-D) Lp^(D-4) = LM n^2
> >
>
> have you noticed that this equation is absolutely independent of setting
> c=h=1 ?
> Just insert
>
> I=n cLp
>
> into your first equation.
>
> I would say, that a choice c=h=1 could prevent you from going further.
> With
>
> Lp = h/Mpc
>
> where Mp is the Planck mass, we have
> IMp = n h
>
> In this quantum relation the purely geometric part I contains the same SI
> space/time units (meter, second) like h, so I/h does not dependent on the
> choice of SI geometric units and means that Mp is proportional to n. If
the
> mass Mp can be divided by n, Mp/n could be more fundamental than Mp.
>
> Where could n come from? Generally, with Mp = h/Lpc and the choice M0 = Mp
> n^(D-3)
>
> R0^(5-D) Lp^(D-4) = n^2 h/M0c = n^(5-D) h/Mpc
>
> we have a fundamental length
>
> R0= n Lp
>
> assuming that I = cR0 is fundamental quantum. Consequently, M0 could be
more
> fundamental than Mp.

[...]

Sorry, just forgot to say:

>From M0(D) = Mp n^(D-3) the mass transformation introduced by varying D

M0(4) = n^2 M0(2)

could provide for a 4D mass value M0(4) strong enough to create a quantum
black hole with a horizon near R0. Simply because

G M0(4) = h c / M0(2) = c I = c^{2R0}

This would be a kind of topological self-consistency. With a simple
Schwartzschild approach, the lighter and lower-dimensional compactified
M0(2) could fit to something like a photon sphere/bubble of a black hole (up
to some numbers, incorporating relativistic corrections should -as far as I
remember- provide for a factor of 3, and 2\pi for the angular dimension).
So n^2 could be assigned not only to topological difference between forces,
but also to a quantum black hole property.

[...]

Regards,
Bernd

[...]

alejandro.rivero
Oct4-04, 12:22 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>"Bernd Binder" &lt;binder@quanics.com&gt; wrote in message news:&lt;cjk27d\\$418\\$1@ngspool-d02.news.aol.com&gt;...\n&gt; Dear Alejandro,\n&gt;\n&gt; "arivero" &lt;arivero@posta.unizar.es&gt; wrote in\n&gt; news:arivero.1c8a8h@physicsforums.com...\n&gt; &gt; A particle in a gravitational circular orbit around a mass M fullfills,\n&gt; &gt; for generical space time dimension D:\n&gt; &gt;\n&gt; &gt; c^2 R^(5-D) Lp^(D-2) = LM I^2\n&gt; &gt;\n\n&gt; have you noticed that this equation is absolutely independent of setting\n&gt; c=h=1 ?\n\nYes, c=h=1 was only for easy read.\n\n\n&gt; into a Newton type relation\n&gt;\n&gt; n^2 G M0^2/R = hc/R\n&gt;\n&gt; we could find a clear interpretation:\n&gt; n^2 M0-masses interacting gravitationally would reach the electromagnetic\n&gt; coupling of about 137 charges at any distance R.\n\nWell, this is completely unrelated to the equations I brought up. Of\ncourse Planck scale\nis the scale where the gravitational force is as strong as the\nelectromagnetic one. That\nis the main idea beyond most allusions to Planck length scales, and it\nis a pity you have\nbeen deluded to use a different constant "n^2 M0" that obscures, more\nthan it illuminates,\nthe point.\n\n\n&gt; With the Planck mass\n&gt; http://scienceworld.wolfram.com/physics/PlanckMass.html\n&gt; and taking M0 as the proton mass we get i.e.\n&gt;\n&gt; n ~ 3*10^19\n&gt; n^2 ~ 9*10^38\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"Bernd Binder" <binder@quanics.com> wrote in message news:<cjk27d$418$1@ngspool-d02.news.aol.com>...
> Dear Alejandro,
>
> "arivero" <arivero@posta.unizar.es> wrote in
> news:arivero.1c8a8h@physicsforums.com...
> > A particle in a gravitational circular orbit around a mass M fullfills,
> > for generical space time dimension D:
> >
> > c^2 R^(5-D) Lp^(D-2) = LM I^2
> >

> have you noticed that this equation is absolutely independent of setting
> c=h=1 ?

Yes, c=h=1 was only for easy read.


> into a Newton type relation
>
> n^2 G M0^2/R = hc/R
>
> we could find a clear interpretation:
> n^2 M0-masses interacting gravitationally would reach the electromagnetic
> coupling of about 137 charges at any distance R.

Well, this is completely unrelated to the equations I brought up. Of
course Planck scale
is the scale where the gravitational force is as strong as the
electromagnetic one. That
is the main idea beyond most allusions to Planck length scales, and it
is a pity you have
been deluded to use a different constant "n^2 M0" that obscures, more
than it illuminates,
the point.


> With the Planck mass
> http://scienceworld.wolfram.com/physics/PlanckMass.html
> and taking M0 as the proton mass we get i.e.
>
> n ~ 3*10^19
> n^2 ~ 9*10^38

Bernd Binder
Oct5-04, 06:42 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>"alejandro.rivero" &lt;arivero@unizar.es&gt; wrote in\nnews:cjs0s1\\$svh\\$1@lfa222122.richmond.edu.. .\n&gt; "Bernd Binder" &lt;binder@quanics.com&gt; wrote in message\nnews:&lt;cjk27d\\$418\\$1@ngspool-d02.news.aol.com&gt;...\n&gt; &gt; Dear Alejandro,\n&gt; &gt;\n&gt; &gt; "arivero" &lt;arivero@posta.unizar.es&gt; wrote in\n&gt; &gt; news:arivero.1c8a8h@physicsforums.com...\n&gt; &gt; &gt; A particle in a gravitational circular orbit around a mass M\nfullfills,\n&gt; &gt; &gt; for generical space time dimension D:\n&gt; &gt; &gt;\n&gt; &gt; &gt; c^2 R^(5-D) Lp^(D-2) = LM I^2\n&gt; &gt; &gt;\n&gt;\n&gt; &gt; have you noticed that this equation is absolutely independent of setting\n&gt; &gt; c=h=1 ?\n&gt;\n&gt; Yes, c=h=1 was only for easy read.\n\nThere is probably no difference. But talking about scales, dimensions, and\nnumbers G=c=h=1 and even h=c=1 could kill information, especially hidden\nquantum numbers like n.\n\n&gt;\n&gt;\n&gt; &gt; into a Newton type relation\n&gt; &gt;\n&gt; &gt; n^2 G M0^2/R = hc/R\n&gt; &gt;\n&gt; &gt; we could find a clear interpretation:\n&gt; &gt; n^2 M0-masses interacting gravitationally would reach the\nelectromagnetic\n&gt; &gt; coupling of about 137 charges at any distance R.\n&gt;\n&gt; Well, this is completely unrelated to the equations I brought up.\n\nReally?\n\n&gt;Of\n&gt; course Planck scale\n&gt; is the scale where the gravitational force is as strong as the\n&gt; electromagnetic one.\n\nNot at all, comparing forces is not so trivial, there is a lot of\ndimensionality/topology, geometry, and symmetry involved.\nPressure, stress and strain relations are highly sensible to dimensional\nconsiderations. But it seems, that the quantum invariant I = cR0 powered by\nyou could be helpful analyzing dimensional effects and comparing forces\nacting in different topologies.\n\n&gt; That\n&gt; is the main idea beyond most allusions to Planck length scales, and it\n&gt; is a pity you have\n&gt; been deluded to use a different constant "n^2 M0" that obscures, more\n&gt; than it illuminates,\n&gt; the point.\n\nR0 could have a direct quantum meaning and is therefore very strong, no\ncomment about it? We know that a lot of work is based on the _assumption_ of\nthe real existence of the Planck scale Rp, probably also your work.\nNevertheless, your formula illuminates the context of th Planck length\nscale: without clarification Rp could be a pseudo length scale if one\nignores the topological differences in fundamental forces.\n\n[...]\n\nBernd\n\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>"alejandro.rivero" <arivero@unizar.es> wrote in
news:cjs0s1$svh$1@lfa222122.richmond.edu...
> "Bernd Binder" <binder@quanics.com> wrote in message
news:<cjk27d$418$1@ngspool-d02.news.aol.com>...
> > Dear Alejandro,
> >
> > "arivero" <arivero@posta.unizar.es> wrote in
> > news:arivero.1c8a8h@physicsforums.com...
> > > A particle in a gravitational circular orbit around a mass M
fullfills,
> > > for generical space time dimension D:
> > >
> > > c^2 R^(5-D) Lp^(D-2) = LM I^2
> > >
>
> > have you noticed that this equation is absolutely independent of setting
> > c=h=1 ?
>
> Yes, c=h=1 was only for easy read.

There is probably no difference. But talking about scales, dimensions, and
numbers G=c=h=1 and even h=c=1 could kill information, especially hidden
quantum numbers like n.

>
>
> > into a Newton type relation
> >
> > n^2 G M0^2/R = hc/R
> >
> > we could find a clear interpretation:
> > n^2 M0-masses interacting gravitationally would reach the
electromagnetic
> > coupling of about 137 charges at any distance R.
>
> Well, this is completely unrelated to the equations I brought up.

Really?

>Of
> course Planck scale
> is the scale where the gravitational force is as strong as the
> electromagnetic one.

Not at all, comparing forces is not so trivial, there is a lot of
dimensionality/topology, geometry, and symmetry involved.
Pressure, stress and strain relations are highly sensible to dimensional
considerations. But it seems, that the quantum invariant I = cR0 powered by
you could be helpful analyzing dimensional effects and comparing forces
acting in different topologies.

> That
> is the main idea beyond most allusions to Planck length scales, and it
> is a pity you have
> been deluded to use a different constant "n^2 M0" that obscures, more
> than it illuminates,
> the point.

R0 could have a direct quantum meaning and is therefore very strong, no
comment about it? We know that a lot of work is based on the _assumption_ of
the real existence of the Planck scale Rp, probably also your work.
Nevertheless, your formula illuminates the context of th Planck length
scale: without clarification Rp could be a pseudo length scale if one
ignores the topological differences in fundamental forces.

[...]

Bernd