electronic engineer
Sep29-10, 04:45 AM
Hello,
I just wanted to know how we moved from the first to the second equation,namely the (-) sign.
L=E\{\left(\frac{\partial}{\partial \theta} \ln f(x,\theta) \right)^2 \}
L= - E \{\frac{\partial^2 }{\partial^2 \theta} ln f(x,\theta) \}
Where E is the mean value.
Thanks
I just wanted to know how we moved from the first to the second equation,namely the (-) sign.
L=E\{\left(\frac{\partial}{\partial \theta} \ln f(x,\theta) \right)^2 \}
L= - E \{\frac{\partial^2 }{\partial^2 \theta} ln f(x,\theta) \}
Where E is the mean value.
Thanks