View Full Version : finding unknown functions
Say you get a problem like this:
Find f(x) and g(x) when f(g(x))=|sin(x)| and g(f(x))=sin^2(sqrt(x)),
and Domain_f=R, Domain_g=[0,-> >
How would you approach to solve this, or do you have to keep guessing until you find two functions that fits?
arildno
Sep16-04, 01:30 PM
Say you get a problem like this:
Find f(x) and g(x) when f(g(x))=|sin(x)| and g(f(x))=sin^2(sqrt(x)),
and Domain_f=R, Domain_g=[0,-> >
How would you approach to solve this, or do you have to keep guessing until you find two functions that fits?
You'll have to keep guessing until you see:
f(x)=sqrt(x)
g(x)=sin^2(x)
Are you sure about the domains?
I was looking for an algorithm or something that would work, when the example wasnt as simple as this one. When alot of simplifying had been done to the expressions for example.
And of course, the domains are reversed. Sorry about that.
arildno
Sep16-04, 01:38 PM
No, there are no general solve-all techniques for functional equations
(where your unknowns are functions, rather than some numbers, for example)
geometer
Sep16-04, 03:03 PM
No, there are no general solve-all techniques for functional equations
(where your unknowns are functions, rather than some numbers, for example)
Of course mathematicians don't want to be perceived as just guessing at possible answers so they have termed this method "solution by inspection." :biggrin:
arildno
Sep16-04, 03:09 PM
Of course mathematicians don't want to be perceived as just guessing at possible answers so they have termed this method "solution by inspection." :biggrin:
:biggrin::biggrin::biggrin::biggrin::biggrin:
Hey, trial and error is a perfectly valid mathematical method! Of course it's not always the most efficient path to a solution. :-)
arildno
Sep17-04, 04:12 AM
Hey, trial and error is a perfectly valid mathematical method! Of course it's not always the most efficient path to a solution. :-)
Well, it's a perfectly valid praxis, don't know about method though..:wink:
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