View Full Version : Hmmm... recurring numbers...
FateMaster
Sep18-04, 05:09 AM
Hihi... I am stumped at this question... I know there is a techique in doin this question... But i forget oredi... Help plz...
Express this recurring number at a fraction of a/b....
Recurring number ---> 0.1454545454545......
Plz explain to me the technique used.... No calculators allowed... :tongue2:
The general trick is to equalise it x multiply by 10^(the number of digits recuring) then take away the orriginal number.
Using your problem as an example.
x = 0.1454545454545...
2 digits are recurring so multiply it be 100
100x = 14.54545454545...
Take away the orriginal number:
100x - x = 14.54545454545... - 0.1454545454545...
Take this a digit at a time:
99x = 14.40000000000...
99x = 14.4
That should be a little easier to solve now :smile:
FateMaster
Sep18-04, 09:56 AM
Stupid me... :rofl:
Thankx.... lol... So its this easy... :surprised
Hehe... Thankx for your help mate.... :blushing: :biggrin:
HallsofIvy
Sep18-04, 11:35 AM
Slightly different way:
Because there is that "1" before the recurring "45", first multiply by 10:
10x= 1.454545...
Now multiply that by 100: 1000 x= 145.454545... and subtract
1000x- 10x= 900x= 144 so x= 144/900
Of course, that gives exactly the same result.
1000x- 10x= 900x= 144 so x= 144/900
Of course, that gives exactly the same result.
Oh, no. Minor snag here. 1000x - 10x = 990x. So the answer really is 144/990. :smile:
You may simplify 144/990, of course.
I like the fact that there are many different ways for solving problems. Here's another method. Not that it is really different: it just differs slightly from all the others.
x = 0.1454545...
10x = 1.454545...
10x - 1 = 0.454545...
We can work out 0.454545... to be 45/99 (100z - z = 45).
10x - 1 = 45/99
10x = (99 + 45)/99
10x = 144/99
x = 144/990
mathwonk
Sep18-04, 03:10 PM
also can do it by "geometric series", really the same again, but done once for all:
i.e. .1 + .045454545...
is .1 Plus the geometric series with initial term a= .045 and ratio r= 1/100, so the sum
is a + ar + ar^2 +......= a/(1-r) i.e. .045/(99/100) = (4.5)/99, so the answer is
.1 + this, as before.
I really do not like this answera s the others's answers are more elementary. but at least it shows how to algebraize their methods.
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