Confusing thermodynamic q

[zmike]

1. The problem statement, all variables and given/known data

1 mole of a gas is burned completely burned in a constant-volume bomb calorimeter at 298 K, 5150 kJ of heat is evolved. Calculate the values delta U and delta H

2. Relevant equations

H = U + W


3. The attempt at a solution

I was lead to believe that you had to calculate number of moles difference delta n by my professor but that lead to no where.

Since constant volume, W = 0?? or does it?

if so then U would be = to qp then shouldn't q=5150 and U = H?

help??

[The legend]

I think...
yes ... you are right that the W=0 and dU=dH but "q=-5150 kJ" since heat is evolved..

so,

dU = q-W
so dU = q

looks like your work's done! :smile:

[Borek]

looks like your work's done! :smile:

If W=0, no work is done :tongue2:

[The legend]

If W=0, no work is done :tongue2:

:rofl: