Minh511@ninhthuanpt.com.vn
Sep20-04, 03:38 AM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\nHow thinking about a modification of FIZEAU experiment?\n\nAccording to the model of Fizeau experiment which were run in 1851, I\ncall:\n- "n" is the refractive index of medium.\n- "u" is the speed of medium in comparison with the laboratory which\nrest on earth.\n- "c/n" is the speed of light in rest medium.\n- "c+" is the speed of light in a same direction of the motional\nmedium.\n- "c-" is the speed of light in a contrary direction of the motional\nmedium.\nAccording to Special Relativity\'s interpretation: The medium represent\nthe K frame, the laboratery (or the earth) represent the K\' frame.\nCalling: "u" is the relative speed of K and K\' frame, "c/n" is the\nspeed of light in the K frame (medium), "c+" and "c_" are the speed of\nlight in K\' frame (laboratory or earth). By the formula for velocity\naddition of Relativity, because of u<<c, after some modifications, The\nlight speed in the motion medium is determined by the formulas:\nc+ » (c/n)+(1-1/n^2)u, c_ » (c/n)-(1-1/n^2)u\nSupposing that the above experiment is executed in a motion spacecraft\nin universal space at vo speed, vo and u are in the same motion\ndirection. In this case, I wonder that:\nHow is it about the achievement result?\nAre there any difference when comparing with a similar experiment\nwhich is run in the rest laboratory on the face of earth?\nAre the achievement values of experiment varied with the change of v0\nspeed of the laboratory?\nWhat can represent the K frame and the K\' frame if use the above\nSpecial Relativity\'s interpretation?\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>How thinking about a modification of FIZEAU experiment?
According to the model of Fizeau experiment which were run in 1851, I
call:
- "n" is the refractive index of medium.
- "u" is the speed of medium in comparison with the laboratory which
rest on earth.
- "c/n" is the speed of light in rest medium.
- "c+" is the speed of light in a same direction of the motional
medium.
- "c-" is the speed of light in a contrary direction of the motional
medium.
According to Special Relativity's interpretation: The medium represent
the K frame, the laboratery (or the earth) represent the K' frame.
Calling: "u" is the relative speed of K and K' frame, "c/n" is the
speed of light in the K frame (medium), "c+" and "c_" are the speed of
light in K' frame (laboratory or earth). By the formula for velocity
addition of Relativity, because of u<<c, after some modifications, The
light speed in the motion medium is determined by the formulas:
c+ » (c/n)+(1-1/n^2)u, c_ » (c/n)-(1-1/n^2)u
Supposing that the above experiment is executed in a motion spacecraft
in universal space at vo speed, vo and u are in the same motion
direction. In this case, I wonder that:
How is it about the achievement result?
Are there any difference when comparing with a similar experiment
which is run in the rest laboratory on the face of earth?
Are the achievement values of experiment varied with the change of v0
speed of the laboratory?
What can represent the K frame and the K' frame if use the above
Special Relativity's interpretation?
According to the model of Fizeau experiment which were run in 1851, I
call:
- "n" is the refractive index of medium.
- "u" is the speed of medium in comparison with the laboratory which
rest on earth.
- "c/n" is the speed of light in rest medium.
- "c+" is the speed of light in a same direction of the motional
medium.
- "c-" is the speed of light in a contrary direction of the motional
medium.
According to Special Relativity's interpretation: The medium represent
the K frame, the laboratery (or the earth) represent the K' frame.
Calling: "u" is the relative speed of K and K' frame, "c/n" is the
speed of light in the K frame (medium), "c+" and "c_" are the speed of
light in K' frame (laboratory or earth). By the formula for velocity
addition of Relativity, because of u<<c, after some modifications, The
light speed in the motion medium is determined by the formulas:
c+ » (c/n)+(1-1/n^2)u, c_ » (c/n)-(1-1/n^2)u
Supposing that the above experiment is executed in a motion spacecraft
in universal space at vo speed, vo and u are in the same motion
direction. In this case, I wonder that:
How is it about the achievement result?
Are there any difference when comparing with a similar experiment
which is run in the rest laboratory on the face of earth?
Are the achievement values of experiment varied with the change of v0
speed of the laboratory?
What can represent the K frame and the K' frame if use the above
Special Relativity's interpretation?