owlman76
Oct20-10, 03:57 PM
1. The problem statement, all variables and given/known data
An Ideal gas and a block of copper have equal volumes V and at the same temperature T and atmosphere pressure P. The pressure on both substances is increased reversibly and isothermally to 5P.
a) Find the work done on the ideal gas if V = 0.5 m and T= 300 K P = 1.01*10^5 Pa
b) Find the work done on the copper using the definition of compressibility k= 0.7*10^-6. for copper
2. Relevant equations
PV=nRT
W= PdV
dW=PVBdT - PVkDP
3. The attempt at a solution
Part A) P1V1=P2V2=nRT SO W = PdV SO W = nRT/V dV SO W= P1V1 * ln(.1/.5) = -81276.6 Joules
I have no idea if that is correct
Part B) dW=PVBdT - PVkDP
Temp is constant so first part drops out so
dW = -PVkdP
My answer was W=-42844 Joules
Any help on solving these equations is awesome.... I don't know if I got either part right or even close to. THANK YOU
An Ideal gas and a block of copper have equal volumes V and at the same temperature T and atmosphere pressure P. The pressure on both substances is increased reversibly and isothermally to 5P.
a) Find the work done on the ideal gas if V = 0.5 m and T= 300 K P = 1.01*10^5 Pa
b) Find the work done on the copper using the definition of compressibility k= 0.7*10^-6. for copper
2. Relevant equations
PV=nRT
W= PdV
dW=PVBdT - PVkDP
3. The attempt at a solution
Part A) P1V1=P2V2=nRT SO W = PdV SO W = nRT/V dV SO W= P1V1 * ln(.1/.5) = -81276.6 Joules
I have no idea if that is correct
Part B) dW=PVBdT - PVkDP
Temp is constant so first part drops out so
dW = -PVkdP
My answer was W=-42844 Joules
Any help on solving these equations is awesome.... I don't know if I got either part right or even close to. THANK YOU