Satellite Orbits: Meteostat Geostationary Orbit Explained

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Discussion Overview

The discussion revolves around the periodic time of the Meteostat satellite in geostationary orbit and why it may not be exactly 24 hours as perceived by an observer on the equator. The scope includes theoretical explanations of orbital mechanics and the distinctions between sidereal and solar days.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions why the Meteostat satellite's periodic time is not exactly 24 hours from an equatorial observer's perspective.
  • Another participant clarifies that the mean motion of the satellite is based on revolutions per sidereal day, which is approximately 1.0027, rather than per solar day.
  • A sidereal day is noted to be 23 hours, 56 minutes, and 4 seconds, providing context for the difference in measurements.
  • It is suggested that Meteostat may not be at the precise altitude required for a 24-hour orbit or that its inclination might not be exactly 0 degrees.
  • Further elaboration indicates that geosynchronous satellites rarely maintain an exact altitude due to orbital perturbations caused by various celestial bodies, which can affect their drift over time.
  • One participant mentions that while inclination does not affect the orbital period, it influences the ground track pattern of the satellite's orbit.

Areas of Agreement / Disagreement

Participants express differing views on the reasons for the Meteostat satellite's periodic time not being exactly 24 hours, with some focusing on the distinction between sidereal and solar days, while others highlight orbital mechanics and perturbations. The discussion remains unresolved regarding the exact cause of the discrepancy.

Contextual Notes

Participants note that the satellite's altitude and inclination may vary, affecting its orbital characteristics. There is also mention of orbital perturbations that complicate the maintenance of a precise geostationary orbit.

Jack16
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Hi People ,Could You Please help me with this question...

There's a satellite called Meteostat which in the geostationary orbit.Could you explain me why its periodic time is not exactly equal to 24 when it is viewed by an observer positioned at a point on the equator...
 
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Where are you getting the idea that it doesn't take 24 hours to reach the same same point above the Earth? If you're looking at mean motion in two line element sets (about 1.0027), it's because mean motion is measuring revolutions per sidereal day, not per solar day.

A sidereal day is measuring the amount of time for the Earth to rotate 360 degrees and a solar day is measuring the amount of time from the Sun being directly overhead to the next time the Sun is directly overhead.
 
A sidereal day being 23 hours, 56 mins and 4 seconds.
 
It may be that Meteostat is either slightly above or below the required altitude for a 24 hour orbit; or its inclination may not be exactly 0 degrees.
 
If you're getting extremely precise, it's almost never exactly at a geosynchronous altitude. Orbital perturbations from the Earth's triaxiality, the Sun, the Moon, and (to a much lesser extent) the planets pull it out of its desired orbit. The rate a geosynchronous satellite drifts depends upon the longitude it's stationed over. Normally, the only significant difference you'll notice is right after the operators maneuver the satellite to compensate for how much it has drifted during the last few months.

Inclination won't affect the period. It'll just affect how big of a 'figure-8' the satellite's ground track makes each orbit.
 
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