Can You Crack the 14-Digit Number Puzzle?

  • Context: High School 
  • Thread starter Thread starter PRodQuanta
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Discussion Overview

The thread discusses a puzzle involving a 14-digit number that begins with 4 and ends with 3, containing two of each digit from 1 to 7, with specific spacing rules between identical digits. Participants are exploring methods to solve the puzzle, including mathematical approaches and trial-and-error techniques.

Discussion Character

  • Exploratory, Debate/contested, Mathematical reasoning

Main Points Raised

  • Paden Roder presents the puzzle and outlines the conditions for the 14-digit number.
  • Another participant suggests a numerical multiplication as a potential solution, but the reasoning behind it is not explained.
  • There is a request for clarification on how the multiplication was derived, indicating a desire for a mathematical explanation.
  • Paden Roder acknowledges the lack of a clear explanation for those who solved it through trial and error, inviting further responses.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the solution method, with some indicating they used trial and error while others are seeking a mathematical explanation.

Contextual Notes

The discussion does not clarify the assumptions behind the multiplication suggested or the specific reasoning for the trial and error approach.

PRodQuanta
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Well, I answered this question in a different forum in quite a hurry. So, if you can get it first, hurray for you.

Problem:
You have a 14 digit number. The number begins with 4 and ends with 3.

The trick:
the number has two of each numbers 1-7 in it. The 7's have 7 spaces between them. The 6's have six spaces in between them. The 5's have 5 spaces in between them. So on and so forth, down to the 1's have 1 space between them.

Ready...
Set...
GO!

Paden Roder
 
Mathematics news on Phys.org
Answer in white:

Multiply 36825889 by 1253777 to find the answer.
 
Eman...please explain how u got it
 
Correctomundo. Like rajesh said, IF you solved this using some mathematical formula, please do tell. If you are like me and just did the trial and error thing, there really is no explanation.

Others feel free to still answer the question.

Paden Roder
 

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