leonne
Feb6-11, 02:43 PM
1. The problem statement, all variables and given/known data
square loop of wire (side a) lies on a table a distance S from very long straight wire which carries current I
A) find flux of B
B) if someone now pulls the loop away from wire at speed V what emf is generated
2. Relevant equations
3. The attempt at a solution
I just have some questions about this problem
A)flux=\int B.da B=uI/2pieS
flux=uI/2pie \int 1/s (ads) my question is why did da become ads? they integrate it from s to s+a
B)\epsilon=-d\phi/dT
\epsilon=-uIa/2pie(d/dt)ln(s+a/s) ds/dt=v
\epsilon=uIa/2pie((1/s+a )ds/dt-1/s(ds/dt) also i have no idea how the got this line.
thanks
square loop of wire (side a) lies on a table a distance S from very long straight wire which carries current I
A) find flux of B
B) if someone now pulls the loop away from wire at speed V what emf is generated
2. Relevant equations
3. The attempt at a solution
I just have some questions about this problem
A)flux=\int B.da B=uI/2pieS
flux=uI/2pie \int 1/s (ads) my question is why did da become ads? they integrate it from s to s+a
B)\epsilon=-d\phi/dT
\epsilon=-uIa/2pie(d/dt)ln(s+a/s) ds/dt=v
\epsilon=uIa/2pie((1/s+a )ds/dt-1/s(ds/dt) also i have no idea how the got this line.
thanks