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npc
Feb15-11, 04:12 AM
Have looked on the forum but can't find this query so hope I am not repeating something that might be here already. Also hope this is the right forum for the post.

1. The problem statement, all variables and given/known data
I am working through a paper on particle motion in GR (Cohen PhysRevD 19,8,p2273) but am running into a few hurdles.


2. Relevant equations

We need to work out radial motion for the general metric:

ds^2=g_{tt}dt^2+g_{rr}dr^2

starting from the Lorentz force equation (for the r-component):

\frac{dp_r}{d\tau}+\Gamma^r_{\alpha\beta}p_\alpha\ frac{dx^\beta}{d\tau}\\=-qF^{r\nu}g_{\nu\beta}\frac{dx^\beta}{d\tau}

where

F_{\mu\lambda}=\partial_\lambda A_\mu-\partial_\mu A_\lambda

and

A_{\mu}=(\psi,0,0,0)

The first problem I have is that the paper gives a result:

\frac{d^2r}{d\tau^2}+\left(\frac{\partial_rg_{tt}} {2g_{tt}}+\frac{\partial_rg_{rr}}{2g_{tt}}\right)\ left(\frac{dr}{d\tau}\right)-\frac{\partial_rg_{tt}}{2g_{rr}g_{tt}}
=-\frac{q}{m}\frac{1}{g_{rr}}\frac{d\psi}{dr}\frac{d t}{d\tau}


whereas I get:

\frac{d^2r}{d\tau^2}+\left(\frac{\partial_rg_{tt}} {2g_{tt}}+\frac{\partial_rg_{rr}}{2g_{tt}}\right)\ left(\frac{dr}{d\tau}\right)^2-\frac{\partial_rg_{tt}}{2g_{rr}g_{tt}}
=-\frac{q}{m}\frac{1}{g_{rr}}\frac{d\psi}{dr}\frac{d t}{d\tau}

Workings in attachment.

just wondering if anyone can see where I am wrong.

Also, The next step in the paper is to say that the above equation has first integral:

\left(\frac{dr}{d\tau}\right)^2=\frac{g_{tt}+(K-\frac{q}{m}\psi)^2}{-g_{tt}g_{rr}}

Where K is a constant of integration.
I can't see where this solution is from, any suggestions on getting it? (probably something obivious)

There is a second integral solution given in the paper:

\frac{dt}{d\tau}=\frac{(K-\frac{q}{m}\psi)}{-g_{tt}}

Which I am able to get correctly from the \mu=t component of the lorentz equation.

3. The attempt at a solution
See attachment
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution