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GWelch
Oct12-04, 08:03 PM
A 3kg weight is on a 35 degree plane, with friction of 0.3. The question is what downward force is needed to hold the weight in place?

I first figured out the Normal Force:
Fn=M Cos 35 degrees
Fn= 24.1 N

Next I figured out the Force of Friction:
Fk= Fn (Uk)
Fk= 7.23 N

Combined Fn and Fk for 31.4 N and called that the force I would need to hold the weight in place. The book answer is 32.2 N, what have I missed?

Thanks in advance for your time and trouble.

Gary