Calculating Force for an Exceptional Standing Jump | 70kg Person | 0.80m Height

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SUMMARY

To calculate the force a 70kg person must exert to achieve a standing jump of 0.80m, one can utilize both kinematic equations and conservation of energy principles. The kinematic approach involves determining the necessary velocity to reach 0.80m and the corresponding acceleration over a 0.20m lowering distance. Alternatively, the energy method focuses on the conservation of mechanical energy, where the total mechanical energy is the sum of kinetic and potential energy. Both methods yield insights into the dynamics of the jump.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet=ma)
  • Familiarity with kinematic equations
  • Knowledge of conservation of mechanical energy
  • Basic principles of projectile motion
NEXT STEPS
  • Calculate the initial velocity required for a 0.80m jump using kinematic equations.
  • Determine the acceleration needed to achieve this velocity over a 0.20m distance.
  • Explore the conservation of energy in isolated systems, focusing on mechanical energy components.
  • Investigate the effects of different body weights on jump force calculations.
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Physicists, sports scientists, coaches, and anyone interested in biomechanics and the physics of jumping performance.

krypt0nite
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An exceptional standing jump would raise a person 0.80 m off the ground. To do this, what force must a 70kg person exert against the ground? Assume the person lowers himself .20m prior to jumping?

Ok, i know i need to find the acceleration and use the Fnet=ma equation but where do i start first?
 
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There are two ways to look at this problem. One way is conservation of energy, the other is kinematic.

For kinematic, you might first look at what velocity is necessary to "throw" an object straight up 0.80 m. Once you have this, then you can look at what acceleration is necessary to reach this velocity within 0.20 m.
 
The energy method is also interesting. Consider the final and initial mechanical energy (which is conserved because this is an isolated system). Remember that [itex]E_{Mechanical}=E_{Kinetic}+E_{Potential}[/itex] here.
 

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