Alem2000
Oct16-04, 10:12 AM
My question is as follows..."An airplane flies in a loop(a circular path in a
vertical plane) of radius 150m. The pilot's head always points
toward the center of the loop. The speed of the airplane is not constant, the
aiplane goes slowest at the top of the loop and fastest at the bottom. a) At
the top of the loop, the pilot feels weightless. What is the speed of the
airplane at this point?"
Since the speed is not constant I would use the formula\sum{\vec{F}}
=m\vec{a}. I then drew a free body diagram, and there were no
horizontal forces and the only vertical force was the weight. So I did this
\sum{F_x}=ma_x=0 and for the y component \sum{F_y}
=ma_y since I chose from 0 and up to be posative on my y
axis i made weight =negative -mg=m\frac{v^2}{R} then I
multiplied both sides by \frac{R}{m} the \frac{-mgR}{m}
=v^2 and then m cancels out and -v=\sqrt{gR}
I think I choose a bad axis system...my answer is the correct
magnitude but...theres that negative sign lurking about... :bugeye: Is it bad
algebra or a bad cordinate system?
vertical plane) of radius 150m. The pilot's head always points
toward the center of the loop. The speed of the airplane is not constant, the
aiplane goes slowest at the top of the loop and fastest at the bottom. a) At
the top of the loop, the pilot feels weightless. What is the speed of the
airplane at this point?"
Since the speed is not constant I would use the formula\sum{\vec{F}}
=m\vec{a}. I then drew a free body diagram, and there were no
horizontal forces and the only vertical force was the weight. So I did this
\sum{F_x}=ma_x=0 and for the y component \sum{F_y}
=ma_y since I chose from 0 and up to be posative on my y
axis i made weight =negative -mg=m\frac{v^2}{R} then I
multiplied both sides by \frac{R}{m} the \frac{-mgR}{m}
=v^2 and then m cancels out and -v=\sqrt{gR}
I think I choose a bad axis system...my answer is the correct
magnitude but...theres that negative sign lurking about... :bugeye: Is it bad
algebra or a bad cordinate system?