What is the force being applied to the box?

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    Applied Box Force
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Homework Help Overview

The discussion revolves around a physics problem involving a box with a specified mass being accelerated across a table, with considerations for friction and forces acting on the box.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss applying Newton's second law and the friction formula, questioning how to incorporate the normal force and friction into their calculations. There are inquiries about the relationship between the normal force and gravitational force, as well as how to rearrange equations to isolate the applied force.

Discussion Status

Participants are actively engaging with the problem, exploring different aspects of the forces involved. Some have provided guidance on how to approach the calculations, while others are clarifying their understanding of the concepts involved. There is a sense of progress as participants build on each other's contributions.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available and the methods they can use. The discussion includes assumptions about the relationships between forces and the definitions of terms like normal force and friction.

ms. confused
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Hi! Is anyone willing to help me with this friction problem?

A box having a mass of 1.5kg is accelerated across a table at 1.5m/s². The coefficient of friction on the box is 0.3. What is the force being applied to the box? :confused:
 
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Use Newton's 2nd Law

[tex]\sum_{i=1}^{n} \vec{F}_{i} = m \vec{a}[/tex]

and remember

[tex]F_{f} = \mu N[/tex]
 
What do I do with the friction formula?
 
Do you know what's the Normal force?
 
Apparently Normal force is equal to Gravitational force so 1.5kg x 9.8m/s² is 14.7N. That should be the Normal force right?
 
Yes, so

Do because there's only acceleration on the x-axis do the forces analysis there.

[tex]F_{applied} - F_{f} = ma[/tex]
 
Do I move everything to one side of the equation to make it equal to zero?
 
ms. confused said:
Do I move everything to one side of the equation to make it equal to zero?

Why would you do that?

Isn't your unknown F applied?

[tex]F_{applied} = ma + F_{f}[/tex]

Mass is known, acceleration is known, [itex]\mu[/itex] is known, and the Normal force is known (so Friction force is known).
 
Ooooooh! Gotcha! Right! Thanks a million!
 

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