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strugglin-physics
Oct18-04, 08:26 AM
How much work is required to stop an electron (m = 9.11×10-31 kg) which is moving with a speed of 1.86×106 m/s?

Ef-Ei=W
Kenetic E - Potential E = Work
I don't think there is any potential energy in this case...

I'm a bit stuck. Any suggestions?

Doc Al
Oct18-04, 08:37 AM
Keep going. W = \Delta {KE}, so what's the kinetic energy of that electron?

strugglin-physics
Oct18-04, 09:05 AM
is the change in kenetic energy 1/2mv^2?

Doc Al
Oct18-04, 09:14 AM
The initial KE of the electron is 1/2mv^2; the final is zero. So, yes, the change in KE is (minus) 1/2mv^2.

strugglin-physics
Oct18-04, 09:21 AM
Great thank you that was a whole lot easier than I made it out to be!