andrew.stewart@anu.edu.au
Oct22-04, 12:40 PM
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no, location=no,scrollbars=yes,resizable=yes,status=no ,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>\n>Over in another Thread I\'ve been involved in a discussion\n>about the Casimir Effect. I\'m hoping that posting a\n>Question here will help resolve the issue. Thanks in\n>advance!\n>\n>As you probably know, the Casimir effect involves two\n>conductive plates placed parallel and very close together.\n>A small force is observed, which tends to push the plates\n>even closer together. According to this link:\n>http://math.ucr.edu/home/baez/physics/Quantum/casimir.html\n>the standard explanation for the presence of that force\n>involves virtual photons in the vacuum. The above-\n>mentioned discussion concerns the effect of ordinary Real\n>photons upon the plates. We are, after all, awash in a\n>sea of Real photons of just about all the longer\n>wavelengths, due to broadcasts around the globe (among\n>other things). Obviously they should bounce off the\n>plates and contribute to the Casimir Effect. Possibly\n>they could explain ALL the Casimir Effect, and then the\n>standard explanation would likely be erroneous.\n>\n>So, has the experiment ever been performed inside a\n>Faraday Cage (a metal box, preferably with no openings),\n>so that all Real photons would be exluded from the\n>vicinity of the two plates? Then, if the Effect occurs,\n>only the standard view would explain it. If not, then\n>the standard view perhaps should be considered faulty.\n>Either result would conclude the above-mentioned\n>discussion.\n>\n>Thanks again! (vnemitz@pinn.net (vernonner3voltazim) )\n------------------------\n\nAll the measurements of Casimir and dispersion forces that have been\nmade are likely to have been made inside a Faraday cage (an\nenclosure, invariably metallic) to protect the experimental system\nfrom external disturbance. Only if the cage is at a temperature of\nzero Kelvin will no "real" photons be present.\n\nAndrew Stewart\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>>Over in another Thread I've been involved in a discussion
>about the Casimir Effect. I'm hoping that posting a
>Question here will help resolve the issue. Thanks in
>advance!
>
>As you probably know, the Casimir effect involves two
>conductive plates placed parallel and very close together.
>A small force is observed, which tends to push the plates
>even closer together. According to this link:
>http://math.ucr.edu/home/baez/physics/Quantum/casimir.html
>the standard explanation for the presence of that force
>involves virtual photons in the vacuum. The above-
>mentioned discussion concerns the effect of ordinary Real
>photons upon the plates. We are, after all, awash in a
>sea of Real photons of just about all the longer
>wavelengths, due to broadcasts around the globe (among
>other things). Obviously they should bounce off the
>plates and contribute to the Casimir Effect. Possibly
>they could explain ALL the Casimir Effect, and then the
>standard explanation would likely be erroneous.
>
>So, has the experiment ever been performed inside a
>Faraday Cage (a metal box, preferably with no openings),
>so that all Real photons would be exluded from the
>vicinity of the two plates? Then, if the Effect occurs,
>only the standard view would explain it. If not, then
>the standard view perhaps should be considered faulty.
>Either result would conclude the above-mentioned
>discussion.
>
>Thanks again! (vnemitz@pinn.net (vernonner3voltazim) )
------------------------
All the measurements of Casimir and dispersion forces that have been
made are likely to have been made inside a Faraday cage (an
enclosure, invariably metallic) to protect the experimental system
from external disturbance. Only if the cage is at a temperature of
zero Kelvin will no "real" photons be present.
Andrew Stewart
>about the Casimir Effect. I'm hoping that posting a
>Question here will help resolve the issue. Thanks in
>advance!
>
>As you probably know, the Casimir effect involves two
>conductive plates placed parallel and very close together.
>A small force is observed, which tends to push the plates
>even closer together. According to this link:
>http://math.ucr.edu/home/baez/physics/Quantum/casimir.html
>the standard explanation for the presence of that force
>involves virtual photons in the vacuum. The above-
>mentioned discussion concerns the effect of ordinary Real
>photons upon the plates. We are, after all, awash in a
>sea of Real photons of just about all the longer
>wavelengths, due to broadcasts around the globe (among
>other things). Obviously they should bounce off the
>plates and contribute to the Casimir Effect. Possibly
>they could explain ALL the Casimir Effect, and then the
>standard explanation would likely be erroneous.
>
>So, has the experiment ever been performed inside a
>Faraday Cage (a metal box, preferably with no openings),
>so that all Real photons would be exluded from the
>vicinity of the two plates? Then, if the Effect occurs,
>only the standard view would explain it. If not, then
>the standard view perhaps should be considered faulty.
>Either result would conclude the above-mentioned
>discussion.
>
>Thanks again! (vnemitz@pinn.net (vernonner3voltazim) )
------------------------
All the measurements of Casimir and dispersion forces that have been
made are likely to have been made inside a Faraday cage (an
enclosure, invariably metallic) to protect the experimental system
from external disturbance. Only if the cage is at a temperature of
zero Kelvin will no "real" photons be present.
Andrew Stewart