Im trying to find the two values of X

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Discussion Overview

The discussion revolves around solving a quadratic equation of the form 0=6x² + x - 1 using the quadratic formula. Participants are examining the application of the formula and the simplification of the resulting expressions to find the two values of X.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant presents their application of the quadratic formula, expressing uncertainty about the correctness of their calculations.
  • Another participant confirms the use of the quadratic formula and suggests that the initial calculations appear correct.
  • A different participant encourages further simplification of the results, providing one of the answers as -1/12.
  • Another participant corrects the earlier expression to x=-1 ± 5 all over 12 and suggests checking the solutions by substituting back into the original equation.
  • Further simplification is proposed, leading to x1 = 1/3 and x2 = -1/2 as potential solutions.

Areas of Agreement / Disagreement

Participants express differing views on the simplification of the quadratic formula results, with some proposing different final values for X. The discussion remains unresolved regarding the final answers.

Contextual Notes

There are unresolved steps in the simplification process, and participants rely on different interpretations of the quadratic formula's application. The accuracy of the final values remains uncertain.

FAQ
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I have this question and I want to know if its correct. I am using the fomula X=-b +/- {root sign} b - 4ac all over 2a

This is the question 0=6x^2 + X + -1
a=6
b=1
c=-1

x=-6 +/- {root sign} 1 - 4(6)(-1) all over 12

x=-6 +/- root 25 all over 12

x=-6 +/- 5 all over 12

Is this the final answer? Did I make a mistake? I am trying to find the two values of X
 
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it is indeed:
[tex]x_{1} = \frac{-b+\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x_{2} = \frac{-b-\sqrt{b^2-4ac}}{2a}[/tex]

for ax²+bx+c = 0

marlon, so it looks ok to me
 
cool thanks, that was quick
 
as always...

marlonissimo
 
Try to see if you can simplify it down further. -6 + 5 = -1 so one of the answers is -1/12.
 
FAQ said:
I have this question and I want to know if its correct. I am using the fomula X=-b +/- {root sign} b - 4ac all over 2a

This is the question 0=6x^2 + X + -1
a=6
b=1
c=-1

x=-6 +/- {root sign} 1 - 4(6)(-1) all over 12

x=-6 +/- root 25 all over 12

x=-6 +/- 5 all over 12

Is this the final answer? Did I make a mistake? I am trying to find the two values of X

it should be: x=-1 +/- 5 all over 12

You can of course always check whether your answer is right by using the answer in the original equation and seeing whether it really gives zero, so
x1 = 4/12
x2 = -6/12
and check whether using x1 and x2 in 6x^2 + X + -1 gives 0
 
gerben said:
it should be: x=-1 +/- 5 all over 12

You can of course always check whether your answer is right by using the answer in the original equation and seeing whether it really gives zero, so
x1 = 4/12
x2 = -6/12
and check whether using x1 and x2 in 6x^2 + X + -1 gives 0

That is right. I didn't check that.

But, that way you can still simplify it further x1 = 1 / 3 and x2 = -1 / 2.
 

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