hulk
Nov14-04, 02:46 PM
A 1550 kg weather rocket accelerates upward at 10m/s^2. It explodes 2 s later after liftoff and breaks into two fragments, one twice as massive as the other. Photos reveal that the lighter fragment traveled straight up and reached a maximum height of 530m.
What was the speed of the heavier fragment just after the explosion.
The way Im approaching is this
Since momentum is conservedd
mv = m1v1 + m2v2
m1 = 500 kg smaller piece
m2 = 1000kg larger piece
I find v
v = at = 20m/s
Iam confused as to how to find v1.
I know only distance gone upward 530m
Should I apply
Vfinal^2 - Vinitial^2 = 2ax where Vfinal is 0 and a is 9.8
This Vfinal is speed of smaller fragment
Once I find this I can find v2 by putting it in momentum eq above.
Im not sure. Can anyone help.
Thankx
What was the speed of the heavier fragment just after the explosion.
The way Im approaching is this
Since momentum is conservedd
mv = m1v1 + m2v2
m1 = 500 kg smaller piece
m2 = 1000kg larger piece
I find v
v = at = 20m/s
Iam confused as to how to find v1.
I know only distance gone upward 530m
Should I apply
Vfinal^2 - Vinitial^2 = 2ax where Vfinal is 0 and a is 9.8
This Vfinal is speed of smaller fragment
Once I find this I can find v2 by putting it in momentum eq above.
Im not sure. Can anyone help.
Thankx