johnsonb.engr
Oct24-11, 08:57 PM
Hello Everybody,
I would greatly appreciated your help. I have been working this problems for the past couple hours and cant seem to find the answer. I tried Google, and opening up my old text books but to no avail. I could really use some help.
I have sample of tungsten coated molybdenum powder. The material is 20% Tungsten by volume and 80 % Molybdenum by weight.
the density of Tungsten = ρw=19.25 g/cm^-3
the density of Molybdenum = ρmo=10.28 g/cm^-3
Obviously ρ=M/V(eqn 1) and Vtotal= Vw + Vmo (eqn 2)
If the material is 20% W by volume, then Vw=0.2*(Vtotal)
Therefore; Vtotal=5Vw
and using eqn 2: 5Vw=Vmo + Vw
4Vw=Vmo
using eqn 1: ρ=M/V; V=M/ρ
And by plunging ρ I obtain,
Vw=Mw/19.25
Vmo=Mmo/10.28
Therefore; 4(Mw/19.25)=Mmo/10.28
Which equals Mw=0.468Mo-------> which makes since because the density of W is ~2x of that of Mo.
However, this is where I am stuck, how do I find the % mass from here using?
FYI....I am trying to solve this theoretically....if this helps the powder I have is 20 % by mass w, has and has an apparent density of 3.0 g.cm^3. Also, when I subjected this powder to a hand held XRF gun, I obtain 94 % Mo and 6 % W.
I would greatly appreciated your help. I have been working this problems for the past couple hours and cant seem to find the answer. I tried Google, and opening up my old text books but to no avail. I could really use some help.
I have sample of tungsten coated molybdenum powder. The material is 20% Tungsten by volume and 80 % Molybdenum by weight.
the density of Tungsten = ρw=19.25 g/cm^-3
the density of Molybdenum = ρmo=10.28 g/cm^-3
Obviously ρ=M/V(eqn 1) and Vtotal= Vw + Vmo (eqn 2)
If the material is 20% W by volume, then Vw=0.2*(Vtotal)
Therefore; Vtotal=5Vw
and using eqn 2: 5Vw=Vmo + Vw
4Vw=Vmo
using eqn 1: ρ=M/V; V=M/ρ
And by plunging ρ I obtain,
Vw=Mw/19.25
Vmo=Mmo/10.28
Therefore; 4(Mw/19.25)=Mmo/10.28
Which equals Mw=0.468Mo-------> which makes since because the density of W is ~2x of that of Mo.
However, this is where I am stuck, how do I find the % mass from here using?
FYI....I am trying to solve this theoretically....if this helps the powder I have is 20 % by mass w, has and has an apparent density of 3.0 g.cm^3. Also, when I subjected this powder to a hand held XRF gun, I obtain 94 % Mo and 6 % W.