georg gill
Nov2-11, 06:23 AM
i wonder about this assignment number 3.10.54:
http://bildr.no/view/1015746
they solve it with derivation:
http://bildr.no/view/1015750
I tried to solve it like this:
x=tan^{-1}(\frac{tan75\cdot 30\cdot0,96}{30})=74,4048
75-74,4048=0,5952 too much error in angle compared to answer sheet
x=tan^{-1}(\frac{tan75\cdot 30\cdot1,04}{30})=75,5523
75,5523-75=0,5523 angle error under value in answer sheet
I dont get this: how come 1,04 of original height gives smaller max error in angle so that by adding that angleerror from the answer one would exceed the assignment of 4 percent of error in height because:
\frac{tan75,57\cdot 30}{tan75\cdot 30}=1,0413
http://bildr.no/view/1015746
they solve it with derivation:
http://bildr.no/view/1015750
I tried to solve it like this:
x=tan^{-1}(\frac{tan75\cdot 30\cdot0,96}{30})=74,4048
75-74,4048=0,5952 too much error in angle compared to answer sheet
x=tan^{-1}(\frac{tan75\cdot 30\cdot1,04}{30})=75,5523
75,5523-75=0,5523 angle error under value in answer sheet
I dont get this: how come 1,04 of original height gives smaller max error in angle so that by adding that angleerror from the answer one would exceed the assignment of 4 percent of error in height because:
\frac{tan75,57\cdot 30}{tan75\cdot 30}=1,0413