How can I do this?Calculating Torque on a Dam Gate Hinged at the Water Surface

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Homework Help Overview

The discussion revolves around calculating the torque on a dam gate that is hinged at the water surface. The gate dimensions are specified as 2 m high and 4 m wide, and participants are exploring the effects of water pressure on the gate's torque due to varying depths.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to calculate the torque from the force exerted by water, noting that pressure increases with depth. There are attempts to derive equations for the force and torque, including integration of a thin horizontal strip's torque over the height of the gate.

Discussion Status

Some participants have provided insights into the relationship between pressure and depth, suggesting methods to calculate the force and torque. However, there is still uncertainty regarding the integration process and the setup of the equations. Multiple interpretations of the problem are being explored without a clear consensus on the approach.

Contextual Notes

Participants are working within the constraints of the problem's geometry and the nature of fluid pressure, questioning how to properly set up their equations for integration. There is an emphasis on understanding the relationship between the variables involved.

gunnar
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There is a gate in a dam. The upper edge of the gate runs along the water surface. The gate is 2 m high and 4 m wide and is hinged along a horizontal line through its center. I have to calculate the torque about the hinge arising from the force due to the water. I know how to calculate torque and water pressure with depth but I have no clue about this problem, I got a clue that tells me to calculate the torque of a thin horizontal strip at a depth h and integrate this over the gate, how should I do that. If someone has a clue, please help me.
 
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gunnar said:
There is a gate in a dam. The upper edge of the gate runs along the water surface. The gate is 2 m high and 4 m wide and is hinged along a horizontal line through its center. I have to calculate the torque about the hinge arising from the force due to the water. I know how to calculate torque and water pressure with depth but I have no clue about this problem, I got a clue that tells me to calculate the torque of a thin horizontal strip at a depth h and integrate this over the gate, how should I do that. If someone has a clue, please help me.

Calculate the hydrodynamical force with which the water acts upon the dam's gate.Use particular geometry of the problem (meaning the perpendicularity between the force and the distance between the point of application and the the center of rotation) to find the torque.

Daniel.
 
There is in fact no problem finding the force on, let's say the bottom of the gate, but the force is not constant on the whole gate because deeper you go into the water, more pressure there is, isn't that correct. So I think my biggest problem is finding a equation for the variables and integrating it, and that's where I'm stuck
 
gunnar said:
There is in fact no problem finding the force on, let's say the bottom of the gate, but the force is not constant on the whole gate because deeper you go into the water, more pressure there is, isn't that correct. So I think my biggest problem is finding a equation for the variables and integrating it, and that's where I'm stuck

It seems like a pretty straightforward problem. Let's take a look at a thin layer of water at height [itex]h[/itex]. Then we can say that the water pressure at that height is [itex]p(h)[/itex]. (We can assume that water pressure at a particular depth is constant.)

Now, the force exerted by water is equal to the pressure multiplied by the area. The area of a thin strip of the gate is going to be [tex]w \times dh[/tex]. So the force at a particular depth will be [tex]f(h)=p(h)\times w \times dh[/tex]. The torque due to the force is going to be [tex](h-h_{pivot}) \times f(h)[/tex], so all you have to do is integrate that from the top of the gate to the bottom:
[tex]\int_{h_{min}}^{h_{max}} (h-h_{pivot}) p(h) w dh[/tex]

Remeber that the sign depends on how your coordinates are set up.
 
OK. Let's see If I got this right.
Lets say that the pivot has height 0 meters, the top of the gate then is 1 and the bottom is -1

The equation that I came up with looks like this:

Torque(h)= (Po + density*g* -h)-4h

What I don't know is how to integrate this equation

I guess I have to integrate once with the limits 0 to 1 and then once with 0 to -1
that way I get the torque on either side of the pivot
 
Last edited:

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