math question

[UrbanXrisis]

I'm not quite sure what the question is asking:
"If f(x)=e^xsin(x), then the number of zeros of f on the interval [o,2pi] is?"

I took the derivative of this and found where it was equal to zero:
f(x)=e^xsin(x)
f'(x)=e^xsin(x)+e^xcos(x)
0=sin(x)+cos(x)

I got zero. However, tha answer is 3, any suggestions?

[Nylex]

No, it wants where the function is zero, not where the gradient of the curve is zero. Where is sin x zero in that interval?

[UrbanXrisis]

you mean when 0=e^xsin(x)?

[dextercioby]

I'm not quite sure what the question is asking:
"If f(x)=e^xsin(x), then the number of zeros of f on the interval [o,2pi] is?"

I took the derivative of this and found where it was equal to zero:
f(x)=e^xsin(x)
f'(x)=e^xsin(x)+e^xcos(x)
0=sin(x)+cos(x)

I got zero. However, tha answer is 3, any suggestions?

e^{x}\sin x=0\Rightarrow \sin x=0
Solve the last equation on the interval [0,2\pi]

Daniel.

[Nylex]

you mean when 0=e^xsin(x)?


Yes, yes I do (sorry had to lengthen my post).

[UrbanXrisis]

it's is zero when x=0, x=pi, x=2pi

so it hits three times!

thanks! Also, why doesnt the e^x make a difference?

[dextercioby]

it's is zero when x=0, x=pi, x=2pi
so it hits three times!
thanks! Also, why doesnt the e^x make a difference?

It never annulates.Not even for complex arguments.

Daniel.

EDIT:Cause it never annulates,it does not affect the zero-s of the function.Plot the graph of 'f'.U'll see quite an interesting behavior.It has no limit for x->+infty.At minus infty it goes to zero.

[UrbanXrisis]

so e^x only increases the sinX amplitude, never now far it streatchs, so it doesnt effect how many times sinX crosses the x-axis

[HallsofIvy]

"Annulates"??? I assume you mean "is never equal to 0" but the only definition I can find of "annulate" is "ring shaped".

UrbanXrises: It's not so much that it is 'always increasing'. In order to solve AB= 0, you solve A= 0 and B= 0. Since ex is never 0, The only solutions of exsin(x)= 0 are where sin(x)= 0.