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Cyrus200
Sep14-03, 04:26 PM
Ok bare with me...
My Symbols are :
^=to the power
X
--= division
Y

Question:
16^x times 32^2x+1
------------------
8^3x-1

= (2^4)^x times (2^5)^2x+1
-----------------------
(2^3)^3x-1

= im stuck here i dont what to do, I got the fractions so that they have the same base but im new to this...I forget the other steps in conquering this question...

My symbols aren't very good because my keyboard doesn't have them unfortunatly.

HallsofIvy
Sep14-03, 08:49 PM
16= 2^4 and 32= 2^5. (2^3)^(3x-1)= 2^(9x-3).

Put those into the equation and see what happens.