How to combine elements of differing ionic charge

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Discussion Overview

The discussion revolves around the combination of elements with differing ionic charges, specifically focusing on the challenges of combining gold (Au) with oxygen (O) and the implications of gold's multiple oxidation states. The scope includes theoretical considerations of ionic compounds and the stability of different oxidation states in chemical reactions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that combining zinc (+2) and chloride (-1) is straightforward, but questions arise when considering gold, which has +1 and +3 oxidation states, in combination with oxygen (-2).
  • Another participant suggests that both oxidation states of gold can be used to form different compounds, highlighting that transition metals often exhibit multiple charges.
  • A further contribution explains that elements with multiple valencies can form various compounds, with the more stable compound typically corresponding to the dominant valency. In the case of gold, the +3 state is generally more stable than the +1 state, particularly when reacting with electronegative elements.
  • It is mentioned that while compounds like AuF3 and AuCl3 are stable, less stable compounds such as AuCl and Au2O exist, and the stability can shift depending on the size of the atoms involved due to steric hindrance.
  • Another participant adds that maximum oxidation states are often realized in fluorides due to fluorine's high reactivity and small size, providing examples from xenon compounds.

Areas of Agreement / Disagreement

Participants express differing views on which oxidation state of gold is preferable for reactions with oxygen, indicating that multiple competing perspectives exist regarding the stability and reactivity of gold's oxidation states.

Contextual Notes

The discussion includes assumptions about the stability of oxidation states and the conditions under which different compounds form, but these assumptions are not universally agreed upon and remain open to interpretation.

relativitydude
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It's easy when say zinc is +2 and chloride is -1, so it is ZCL2

However, say I wanted to combine say, oxygen and gold. Gold has +1 and +3 and oxygen is -2, which of the gold do I use? (+1 or +3, for example)
 
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I believe you can use both. [tex]AuCl_3[/tex][tex]AuCl[/tex] They are different compounds of gold. a lot of transition metals have more than 1 charge.

o ya, I used chlorine because gold is not very reative, only with chlorine and fluorine. :approve:
 
As DB's said already, elements that exhibit multiple valency form more than one compound with another element (as long as the two will react). The dominant valency leads to the more stable compound. Less favored valencies (or oxidation states) result in less stable, or more reactive compounds.

In tha case of Au, the +3 state is much more stable than the +1 state (the reason for this is a little complicated). But gold itself is quite an unreactive metal, so it will react only with the most electronegative elements like the halogens (F, Cl, Br, I) and the chalcogens (O, S, Se, Te).

Since the +3 state is preferred, compounds like AuF3, AuCl3, AuBr3, Au2O3 are quite stable. However, AuCl, AuBr, Au2O also exist, though they are less stable. But when you get to the bigger atoms (Se, I), it becomes difficult to squeeze 3 of these around a gold atom. The repulsion between these atoms (also known as steric hindrance) becomes very strong. So, with the bigger atoms, the +1 state is preferred, and so, in these cases AU2Se and AuI are the more stable compounds.

This is just a crude explanation, and the details are far more complex. But the general lesson to be learned is that, when an element exhibits multiple valencies (this is particularly pronounced with the d-block, or transition metals), it will form multiple compounds with another element, their stabilities generally depending on the dominance of the valency.
 
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To add a little,the maximum oxydation states is usually realized in fluorides,as the fluorine is the most rectiv nonmetal,plus it has the 'smallest' molecule among the halogens.It sometimes occurs with the oxygen,too.
E.g.Xe (54) has the oxydation states:+2,+4,+6,+8.The maximum one is encontered in the octofluorine:[itex]XeF_{8} [/tex] and the tetraoxyde:[itex]XeO_{4}[/itex].<br /> <br /> <br /> Daniel.[/itex]
 

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