Determine the magnetic field between 2 long straight wires

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SUMMARY

The discussion focuses on calculating the magnetic field between two long straight wires separated by 2 cm, with one wire carrying a current of 15A and the other carrying an unknown current (I). When the currents flow in the same direction, the magnetic field at the midpoint is determined using the formula B = (μ₀ I) / (2π r) and the superposition principle. The magnetic field strength is influenced by the distance between the wires and the current values, while the length of the wires is not a factor in this specific calculation.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with the Biot-Savart Law
  • Knowledge of the right-hand rule for magnetic fields
  • Basic principles of electromagnetism
NEXT STEPS
  • Study the application of Ampère's Law in various configurations
  • Learn about the Biot-Savart Law for calculating magnetic fields
  • Explore the concept of magnetic field superposition in multiple wire systems
  • Investigate the effects of varying current directions on magnetic field interactions
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Physics students, electrical engineers, and anyone interested in understanding magnetic fields generated by current-carrying conductors.

joej
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determine the magnetic field between 2 long straight wires 2cm apart in terms of the current (I) in one, when the other carries 15A. Assume currents are in the same direction.

okay so if they're in the same direction the field should be up

now I'm guessing I should use (4pi x 10^ -7)/(2pi) (I1 x I2)/(d) = F/l

now from that I'm guessing the length of the wire is no a factor here

so I get ((2 x 10 ^ -7)(I1 x I2))/d = F

now... where should I go from here?
 
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Use the formula for the magnetic field of a(n) (infinitely) long wire:

[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]

plus the superposition principle to find the field at a point between the wires.
 
joej said:
determine the magnetic field between 2 long straight wires 2cm apart in terms of the current (I) in one, when the other carries 15A. Assume currents are in the same direction.

okay so if they're in the same direction the field should be up
At the midpoint between the two wires, they are equally strong and in opposite directions. Use the right hand rule to find direction of B for each wire.

now I'm guessing I should use (4pi x 10^ -7)/(2pi) (I1 x I2)/(d) = F/l

now from that I'm guessing the length of the wire is no a factor here

so I get ((2 x 10 ^ -7)(I1 x I2))/d = F
[tex]2\pi rB = \mu_0I[/tex] for each wire. You can't find the magnetic force between the two wires unless you know their length.

AM
 

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