Methods that were used to solve the ODE

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Discussion Overview

The discussion revolves around the algebraic manipulation of two expressions related to an ordinary differential equation (ODE). Participants explore whether one expression can be transformed into another through algebraic methods, specifically focusing on the equivalence of the forms presented in the problem.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant seeks assistance in algebraically manipulating the expression xy=c(y+√(y²-x²)) to resemble y²-cx=y√(y²-x²).
  • Another participant suggests that proving the equivalence algebraically is essential and hints at solving both equations for c as a potential method.
  • A later reply encourages the idea of "rationalizing" the right-hand side (RHS) of the equation as a strategy for manipulation.
  • One participant shares their experience of solving for c first and agrees that rationalizing was a useful approach given the placement of the radical in the expressions.
  • Another participant expresses their struggle with algebra and acknowledges the need for regular practice to improve their skills.

Areas of Agreement / Disagreement

Participants generally agree on the potential of algebraic manipulation to show the equivalence of the expressions, but there is no consensus on the specific methods or steps required to achieve this transformation.

Contextual Notes

Participants mention the challenge of handling radicals and the importance of recognizing when to apply certain algebraic techniques, indicating a reliance on personal experience and intuition rather than a definitive method.

Who May Find This Useful

Individuals interested in algebraic manipulation, particularly in the context of solving differential equations or improving their mathematical reasoning skills.

NeutronStar
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Can anyone show me how to make this:

[tex]xy=c\left( y+\sqrt{y^2-x^2}\right)[/tex]

Look like this:

[tex]y^2-cx=y\sqrt{ y^2-x^2}[/tex]

These were given as the answers to an ODE problem.

I'm assuming that they are equivalent because they are presented in the answer as:

[itex]y^2-cx=y\sqrt{ y^2-x^2}[/itex], or equivalently [itex]xy=c\left( y+\sqrt{y^2-x^2}\right)[/itex]

I got the second answer but I can't figure out how to algebraically manipulated it to make look like the first.

Any takers?

P.S. I'm not certain if it can even be done algebraically. It might have something to do with the methods that were used to solve the ODE. But if they are equivalent answers it should be possible to obtain one from the other using just algebra shouldn't it?

My algebra skills suck!
 
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It's true iff it can be proven algebraically. (Hurrah for abstract mathematics)

The method might become clear if you try solving both equations for c.

Better hint in white:


Try "rationalizing" the RHS -- multiply through by y - √(y2 - x2). (and handle specially the case where this actually equals zero)
 
Hurkyl said:
Try "rationalizing" --
Ok, that was specifically the hint that I needed. :biggrin:

I guess I need to start doing some algebra problems everyday like morning calisthenics or something. It's hard to do algebra if you aren't doing it every day. I pretty much know how to do all the tricks, I just can never figure out which trick to pull out of the bag to achieve my final goals!

Thanks for the tip! :approve:
 
Just FYI, I solved for c first. I figured rationalizing was the way to go, because one expression had the radical in the numerator, and the other on the denominator.
 
Hurkyl said:
Just FYI, I solved for c first. I figured rationalizing was the way to go, because one expression had the radical in the numerator, and the other on the denominator.
That little tid-bit of wisdom will definitely be useful to me in the future. To be perfectly honest, I'm so rusty with algebra that even that hint starting me in the face wouldn't have done much for me. But from now on when I see that situation I'll be thinking "rationalize!" :wink:

I'm just so rusty it's embarrassing. :blushing:
 

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