Stoichiometry Help: Calculating Moles & Grams of O

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SUMMARY

The discussion focuses on stoichiometry calculations involving moles and grams of substances, specifically sugar (C12H22O11) and aluminum potassium sulfate dodecahydrate (AlK(SO4)2·12H2O). To find the number of moles of sugar in a tablespoon weighing 2.85g, the molar mass of sugar must be calculated and then divided into 2.85g. For calculating grams of oxygen in sugar, the number of moles is multiplied by the molar mass of oxygen and the number of oxygen atoms present. In the second problem, to find grams of oxygen in 1.555×10-5 moles of AlK(SO4)2·12H2O, the moles should be multiplied by the molar mass of the compound.

PREREQUISITES
  • Understanding of molar mass calculations
  • Knowledge of stoichiometry principles
  • Familiarity with chemical formulas and molecular composition
  • Basic arithmetic operations for unit conversions
NEXT STEPS
  • Calculate the molar mass of C12H22O11
  • Learn how to determine the molar mass of AlK(SO4)2·12H2O
  • Study stoichiometric conversions between moles and grams
  • Explore the concept of limiting reagents in chemical reactions
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Chemistry students, educators, and anyone involved in chemical calculations or stoichiometry will benefit from this discussion.

gokugreene
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Hey could you guys tell me whether I am on the right track with this or not.

First Problem:
A tablespoon of sugar, [tex]C_1_2H_2_2O_1_1[/tex], weighs 2.85g.
A.) How many moles of sugar are there in a tablespoon?

Do I calculate the molar mass of sugar in grams and then divide 2.85g by the molar mass? To give me the moles?

Also, if I were to calculate how many grams of O there are in 2.85g of sugar would I just multiply the number of moles in 2.85g of sugar by the molar mass of oxygen times the number of oxygen atoms?

Second Problem:
Sample A is [tex]1.555~x~10^{-5}[/tex] mole of [tex]AlK (SO_4)_2~12H_2O[/tex]
A.) How many grams of O are present?
Do I start by multipliying [tex]1.555~x~10^{-5}[/tex] by the molar mass of [tex]AlK (SO_4)_2~12H_2O[/tex]??

Thanks
 
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