Answer:Work-Energy Scaling: R_k,R_w = 3,1

[ProBasket]

A particle of mass $$M$$ moves along a straight line with initial speed $$v_i$$. A force of magnitude $$F$$pushes the particle a distance $$D$$ along the direction of its motion.

assume that the particle's mass is increased to 3M.

B.)By what multiplicative factor $$R_k$$ does the initial kinetic energy increase, and by what multiplicative factor $$R_w$$ does the work done by the force increase (with respect to the case when the particle had a mass $$M$$)

If one of the quantities doubles, for instance, it would increase by a factor of 2. If a quantity stays the same, then the multiplicative factor would be 1.

You should enter the two factors separated by a comma.

$$R_k,R_w = ___________$$



this is what i think:

to find $$R_k$$ i must use this formula: 1/2*m*v^2
to find $$R_W$$, i must use this formula: W=f*d

okay, now to find r_k: 1/2*M*v^2 = 3M (cancel everything and get only 3)

now to find r_w:
$$W = 1/2*M*v_i^2+F*D -1/2*M*v_i^2 = 1/2*3M*v_i^2+F*D -1/2*3M*v_i^2$$ <-- i get 0, is this correct?

i'm pretty sure I'm doing it incorrectly, but i don't know how to correct it. can someone help?

 

[stunner5000pt]

what does Rk and Rw correspond? does Rk or Rw ask for the 3M part or the M part??

Please type out the question exactly how you read it. This doesn't make any sense otherwise.

 

[ProBasket]

i copied the whole thing (it's online,so i just copied and pasted). but R_K is kinetic energy multiplicative factor and R_w is tk work multiplicative factor

edit: i just figured it out, thanks anyways