Can someone point me in the right direction

[powp]

Hello

I have to simplify the following expression can anybody help me get started??

$$\frac{\frac{-3xy^{-2}}{x-1}}{10(\frac{xy}{z^3})^{-2}}$$

Thanks

P

 

[Crosson]

The first thing is to take care of the negative exponent, then divide the fractions (by multiplying by the reciprical).

 

[powp]

Sorry I miss typed the problem(I think hard to tell)
$$\frac{\frac{-3xy^{-2}}{z^{-1}}}{10(\frac{xy}{z^3})^{-2}}$$

So this is what I have so far

$$\frac{\frac{-3xz^{1}}{y^{2}}}{10(\frac{z^3}{xy})^{2}}$$

$$\frac{\frac{-3xz^{1}}{y^{2}}}{10(\frac{z^6}{x^2y^2})}$$

$$\frac{\frac{-3xz^{1}}{y^{2}}}{(\frac{10z^6}{10x^2y^2})}$$

$${\frac{-3xz^{1}}{y^{2}}}X{\frac{10x^2y^2}{10z^6}$$

Am I on the right track?

 

[b0mb0nika]

yeah except one thing:
when you multiply the faction by 10, it only goes on the top, not on the bottom. So then when you invert it, its going to be on the botton
(x^2)(y^2) / (10 z^6)
the rest is fine now u just need to cancel the y^2 and the z

 

[powp]

so it is ?

$${\frac{-3xz^{1}}{y^{2}}}X{\frac{x^2y^2}{10z^6}$$

how do the z cancel each other out?

 

[dextercioby]

They don't

$$\frac{-3}{10}\frac{x^{3}}{z^{5}}$$


Daniel.

 

[powp]

does it work out like this??

$${\frac{-3x^3y^2z^1}{10y^{2}z^6}}$$

$${\frac{-3x^3y^{2-2}z^{1-6}}{10}}$$

$${\frac{-3x^3y^{0}z^{-5}}{10}}$$

$${\frac{-3x^3}{10z^{5}}}$$

 

[dextercioby]

Exactly like that.

Daniel.

 

[powp]

Thanks for you help