View Full Version : Help Yet Again...
OK, problem with this equation:
x^4 + 2x^2 + x + 2 = 0
What is/are the solution(s)? I can't figure out how to factor this so that I can find the zeros or whatever...
Integral
Oct5-03, 09:43 PM
Hint: It has no Real zeros.
phoenixthoth
Oct6-03, 01:24 AM
it is possible to factor it over the integers.
suppose you have a polynomial P of degree p. you want to factor it as P = Q R where Q and R are polynomials. consider the different degrees Q and R might have if p = 4 as in your case. this consideration will direct the trials and errors when looking for Q and R.
How can I prove that I have no zeros?
phoenixthoth
Oct6-03, 10:39 AM
that'll be clear once you factor it.
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