Calculating Forces on a 2000kg Elevator Suspended by Single Cable

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Homework Help Overview

The discussion revolves around calculating the forces acting on a 2000 kg elevator suspended by a single cable, specifically when it is at rest and when it is descending with an acceleration of 4.0 m/s². Participants explore the implications of gravitational force and tension in the context of the elevator's motion.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law (F=ma) in scenarios of rest and acceleration, questioning how to account for forces when the elevator is at rest versus when it is descending. There is also a focus on distinguishing between tension and gravitational forces.

Discussion Status

The discussion is active, with participants providing insights into the calculations of forces, including gravitational force and tension. There is a mix of interpretations regarding the direction of acceleration and its effect on the net forces acting on the elevator.

Contextual Notes

Participants reference specific values for gravitational acceleration and discuss the implications of the elevator's motion, including whether it is accelerating upward or downward. There is an emphasis on understanding the relationship between tension and gravitational force in this context.

Power24
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Elevator of 2000kg is suspended by a single cable calculate the forces on it while it is at rest.

F=ma
well it's at rest so there is 0 acceleration, does that mean the formula is not usable or is it simply 2000N?

partc asks what the value of all forces is at 4.0 m/s^2, would that just be F=2000(4) then F=8000N
 
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Actually gravity exerts a force of 2000g downward while the roof pulls it up with the same force, and the total net force=0.
 
ok well the question is, calculate all the forces acting on the elevator

c) calculate all the forces acting on the elevator when descending 4.0 m/s^2
 
Gravity and normal force which are equal.
 
it's actually tension and gravity but I need to find the value in Newtons
 
9.81*2000=Fg... Same for tension.
 
much appreciated but the value 9.8, I remember it from an example, it has to do with gravity, gravities acceleration is 9.8m/s^2 so assuming that's where its coming from a value of 4.0m/s^2 descending would give me an equation of F=2000(5.8)
 
You mean the Elevetor is accelerating 4 m/s^2 upward? Gravity stays the same, 9.81(2000) and then torsion (I call it normal force, it is just a matter of what the force is going trought) will be equal to 2000(9.81+4)
 
yes it accelerating but it's going downward so does that make a difference?
 
  • #10
If it accelerates downward then its substracted from gravity so 5.8 upward is right.
 
  • #11
Perfect, thanks for the help.
 

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