Ok soon to be algebra teacher i can feel it last one i think

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    Algebra Teacher
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Homework Help Overview

The discussion revolves around solving an inequality involving algebraic expressions. The original poster is seeking clarification on the rules for changing inequality signs during operations, particularly in the context of division and multiplication by negative numbers.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the steps involved in manipulating the inequality, questioning the correctness of sign changes and the operations performed. There is a focus on understanding when and why the inequality sign changes, particularly in relation to division and multiplication by negative numbers.

Discussion Status

Participants are actively engaging with each other's reasoning, providing feedback on the steps taken, and offering advice on how to approach the problem more clearly. There is no explicit consensus on the final answer, but guidance has been shared regarding the process of solving inequalities.

Contextual Notes

The original poster mentions a constraint regarding their son's access to resources, as he does not have his book available for reference. This may impact the clarity of their understanding of the rules being discussed.

thomas576
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2(x-5)-(3x+3)<x-7
2x-10--3x-3<x-7
-1x-13<x-7
0<6


i can't find the rules for when the sign changes my son is convinced that if you only divide then the sign changes to > i don't remember and he of course has his book in school :mad:
 
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I don't see where division has entered the picture. :-p

(The last step is wrong)

Multiplying or dividing by a negative number flips the sign of an inequality.
 
division part

i was referring to the < sign i remember them having to change for a reason, he says only if your dividing, i thought maybe it was for sign change but i think you answered me :0 let me look at last line again
 
2(x-5)-(3x+3)<x-7
2x-10-3x-3<x-7
-1x-13<x-7
-13+7<2x
-6<2x
-3<x
x>-3
 
hmm again

2(x-5)-(3x+3)<x-7
2x-10--3x-3<x-7
-1x-13<x-7 so -1x-1x is 2x<6 and that is x<3?

whoray! did i get it! looks like it works!
 
You sure -1x - 1x = 2x?
 
Some little advice, I noticed you seem to do many steps in one line, slow it down and write it out more. It may take up more paper, but it actually saves paper because you will likely find the answer with less trys.

Also, in these single variable problems, try to get the equation so that one side is only variables and the other side numbers.
 
hmm i was close, thanks all my brain is fried I am done for the night. i thank you all and my son will enjoy life without the phone tomorrow for starting this at 10pm :) I am glad you all were kind enuf to help thank you for your time!

thomas
 

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