What is the phase difference between the two radio waves

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Homework Help Overview

The problem involves two antennas radiating in phase and a receiver that measures the intensity of the waves. The receiver is moved closer to one antenna, and the task is to determine the phase difference between the two radio waves based on the path difference created by this movement.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for phase difference and question the calculation of the path difference, specifically whether it is simply the 1.8 m or if trigonometry is required to determine the distances involved.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the relationship between the path difference and the distances to the antennas. Some guidance has been offered regarding the interpretation of the variables r_1 and r_2, but no consensus has been reached on the need for trigonometric calculations.

Contextual Notes

Participants are working under the constraints of the problem as stated, with specific attention to the definitions of r_1 and r_2 in relation to the receiver's position. There is an emphasis on understanding the implications of being 1.8 m closer to one antenna.

sghaussi
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Hello, I am having difficulty answering the following problem:

consider two antennas, separated by X meters that radiate in phase at f. A reciever placed 150 m from both antennas measures an intensity I_o. The reciever is moved so that it is 1.8 m closer to one antenna than ot the other.

What is the phase difference between the two radio waves produced by the path difference?


okay. so I know i want to use the formula: phase diff = 2pi/lamda*(r_2 - r_1)

i was able to calculate lamda, however I'm not sure about the path difference. Would that be my 1.8 m?? or is there trig involved here in order to figure out r_2 - r_1 ??
 
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sghaussi said:
Hello, I am having difficulty answering the following problem:

consider two antennas, separated by X meters that radiate in phase at f. A reciever placed 150 m from both antennas measures an intensity I_o. The reciever is moved so that it is 1.8 m closer to one antenna than ot the other.

What is the phase difference between the two radio waves produced by the path difference?


okay. so I know i want to use the formula: phase diff = 2pi/lamda*(r_2 - r_1)

i was able to calculate lamda, however I'm not sure about the path difference. Would that be my 1.8 m?? or is there trig involved here in order to figure out r_2 - r_1 ??

The reciever is moved so that it is 1.8 m closer to one antenna than to the other.
 
so does that mean it is hte path difference?
 
do I use trig here or is hte phase difference already given?
 
sghaussi said:
so does that mean it is hte path difference?

Do you understand what r_1 and r_2 are? They are not just letters in a formula. They represent two distances. They are:

r_1 = distance to antenna 1 from the location where you are receiving the wave

r_2 = distance to antenna 2 from the location where you are receiving the wave

If you are 1.8m closer to one antenna than you are to the other, what must r_2 - r_1 be?

You need to ponder this question until you figure out the answer. It will do you no good for someone to give you the direct answer you want about needing or not needing to apply trig.
 

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