Does Producing Sulfuric Acid from Copper Sulfate Pentahydrate Release Oxygen?

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SUMMARY

The production of sulfuric acid from copper sulfate pentahydrate involves heating the compound to yield copper dioxide, water, and sulfur trioxide. The reaction can be summarized as SO3(g) + H2O(l) → H2SO4(l). This process does not release oxygen as a byproduct, as the chemical signatures indicate that oxygen is not produced during the breakdown of copper sulfate pentahydrate. Additionally, the reverse process of combining copper dioxide and sulfuric acid to regenerate copper sulfate pentahydrate is not straightforward, as it requires specific conditions and additional reactants.

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LURCH
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I was recently reading about the method by which sulfuric acid was produced in the old days. Apparently, copper sulfate pentahydrate (green vitriol), when heated up, breaks down into copper dioxide, water, and sulfur trioxide. The sulfur trioxide and water then bond to form sulfuric acid. Now, I'm really weak on chemistry, but by looking at the chemical signatures of these substances it appears that an oxygen molecule is missing. Does this method give off oxygen as a byproduct?

Also, can the process be reversed? Can copper dioxide and sulfuric acid be combined to form green vitriol?
 
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what is missing?

[tex]SO_3(g) + H_2O(l) \longrightarrow H_2SO_4(l)[/tex]

where are we missing oxygen?
 

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