Physics Help sound level intensity

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SUMMARY

The discussion centers on calculating sound level intensity when one of three equally noisy jet engines is shut down, starting from a baseline of 120 dB. The initial calculation incorrectly suggested a sound level of 125 dB after one engine was turned off. The correct approach involves understanding the logarithmic relationship of sound intensity, specifically using the formula for sound levels and the ratio of intensities for three versus two engines. The correct sound level should be lower than 120 dB, reflecting the reduction in engine noise.

PREREQUISITES
  • Understanding of sound intensity levels and decibels (dB)
  • Familiarity with logarithmic calculations
  • Knowledge of the inverse square law in sound propagation
  • Basic principles of acoustics and sound sources
NEXT STEPS
  • Study the formula for sound intensity levels in decibels
  • Learn about the logarithmic scale and its application in acoustics
  • Research the effects of multiple sound sources on overall sound intensity
  • Explore the concept of sound intensity ratios and their calculations
USEFUL FOR

Acoustics students, sound engineers, and anyone interested in understanding the principles of sound intensity and its calculations in real-world scenarios.

smith22
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A person standing a certain distance from an airplane with three equally noisy jet engines is feeling a sound level intensity bordering on pain, 120dB. What sound level would this person experience if the captain shut down one engine?

this is what I did:
B-120=10log.33
and ended up with 125 dB as the intensity

What am I doing wrong since I am reducing the factor by 3 and its still not working?
 
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I see two problems:

(1) The sound level should be lower with only two engines running: log.33 is negative.

(2) You have the wrong ratio of intensities: What's the ratio of intensities for 3 engines versus 2 engines?
 
smith22 said:
A person standing a certain distance from an airplane with three equally noisy jet engines is feeling a sound level intensity bordering on pain, 120dB. What sound level would this person experience if the captain shut down one engine?

this is what I did:
B-120=10log.33
and ended up with 125 dB as the intensity

What am I doing wrong since I am reducing the factor by 3 and its still not working?
let I0 be ref sound intensity level
sound level (db) w/3 engines = 120 db = 10 log10( 3(I/I0) )
= 10 log10(3) + 10 log10( I/I0 )
= 10 log10(2*(3/2)) + 10 log10( I/I0 )
= 10 log10(3/2) + 10 log10(2) + 10 log10( I/I0 )
= 10 log10(3/2) + 10 log10( 2(I/I0) )
= 10 log10(3/2) + (sound level (db) w/2 engines)
 

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