Power in delevering electricity to a factory

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SUMMARY

The discussion focuses on calculating power loss in electrical transmission to a factory, specifically comparing two voltage levels: 45200V and 13900V. The power station delivers 513kW, and the total resistance of the wires is 2.72 Ohm. By applying the formulas P=I^2R and P=VI, participants explore how to determine the initial current and subsequently calculate the power wasted due to resistance at both voltage levels. The key takeaway is that higher voltage results in significantly less power loss in the transmission lines.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with power formulas (P=VI and P=I^2R)
  • Basic knowledge of electrical resistance and its impact on power loss
  • Ability to perform calculations involving voltage, current, and resistance
NEXT STEPS
  • Calculate power loss using P=I^2R for different voltage levels
  • Explore the benefits of high-voltage transmission systems
  • Learn about electrical efficiency and its importance in industrial applications
  • Investigate the role of transformers in voltage regulation and power delivery
USEFUL FOR

Electrical engineers, factory managers, and anyone involved in power distribution and efficiency optimization in industrial settings.

melissa_y
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A power station delivers 513kW of power to a factory through wires of total resistance of 2.72Ohm. How much less power is wasted if the electricity is delivered at 45200V rather than 13900V?

I have no idea where to even begin except that I should find the intial current which is found by equation P=I^2R

Please help me!
 
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you can also use the fact of p = I^2R = V^2 / R
 
Voltage is equal to: V=IR

So, if the power is equal to [tex]P=RI^2[/tex], then it's also equal to [tex]P=VI[/tex]

The current being delivered to the circuit comes from the Power and Voltage relationsip.

To find how much power is lost, you have a new problem that uses the result of the first (you had to solve for I). You use the [tex]P=RI^2[/tex] to find out how much power is dissipated by the wire.

Change the value of the voltage and repeat. Compare the two results.
 

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