How High Will Tarzan Swing on the Vine?

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    Grade 11 Physics
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Homework Help Overview

The problem involves a physics question related to the motion of Tarzan swinging on a vine, specifically determining how high he will swing based on his initial speed. The subject area is kinematics and energy conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of energy conservation principles, questioning the initial conditions of Tarzan's velocity and its components. There is confusion regarding the interpretation of the problem, particularly about the direction of velocity and its effect on the swing height.

Discussion Status

The discussion includes attempts to clarify the initial conditions and the relationship between horizontal and vertical velocities. Some participants have reached a numerical agreement on the height but are exploring the implications of velocity components and the nature of the swing.

Contextual Notes

There is uncertainty regarding the initial velocity's direction and whether additional information, such as an angle, is necessary for a complete understanding of the problem. Participants are navigating the constraints of the question as it was presented in a test context.

LiquidIce
Need Help Grade 11 physics question!

The question is something like this I am not sure exactly because it was on my test.

Tarzan is running at 8.0 m/s and jumps onto a vine. How high above the bottom of his swing will he go ?

Plz help i have no clue how to do this
 
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1/2mv^2 = mgh
1/2v^2 = gh
h=1/2(8)^2/10=3.2 m
 
You must know his velocity in the Y direction or up. If you were given and angle, then it can be broken down.

If he only has a velocity of 8 m/s in the X direction, then he will not leave the ground.

Nautica
 
thanks a lot i figured it out i got the same answer as u 3.2 i think i need to find the velocity so do i just double the 3.2 and make it 6.4?
 
meister hit the nail on the head.
What do you mean find the velocity? When he starts off, his X velocity is 8 and his Y is 0; at the peak of his swing, both x and y are 0.
 
I see now, I was reading it as how far up he would jump onto the swing?

Nautica
 

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