Solving the Ramp Problem: Finding Time to Stop Sliding on a Horizontal Surface

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SUMMARY

The discussion focuses on calculating the time it takes for an object to stop sliding on a horizontal surface after descending an incline with an angle of Θ = 6.9 degrees. The object slides at a constant velocity of 1.4 m/s, and the coefficient of friction on the horizontal surface is determined to be μ = 0.12101, derived from the equation tan(Θ) = μ. The net force acting on the object is zero during its descent, and the friction force on the horizontal surface is calculated as |f| = μmg, leading to an acceleration of a = -μg. The time to come to rest can be found using the kinematic equation v = vo + at.

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Ninja_P
I would really appreciate some help on this problem, or even a push in the right direction:

An object of unknown mass slides down an incline in which Θ= 6.9. The object slides with a constant velocity of 1.4 m/s. At the bottom of the incline, the object slides on to a horizontal in which the coefficient of friction is the same as the incline. This is neglecting air resistance and the transfer of the object from incline to flat surface. I'm trying to figure out how long it will take the object to cease movement after it begins to slide on the horizontal surface.

So far I've been able to figure out:
Fnet = 0 since acceleration = 0.
Force of friction = Force parallel since Fnet = 0.
μ = 0.12101 because of tanθ = μ

Any help is greatly appreciated.
 
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Sorry, I forgot to add what equations I know already.

Of course, Fnet = ma
Normal Force = Weight x cosΘ On the horizontal -> W = mg
Parallel Force = Weight x sinΘ
Friction Force = μ x Weight x cosΘ (Normal Force)
and my four kinematics equations.
 
When you're on the horizontal part, the only force that is in the direction of motion is the friction force, which is now |f| = μmg. Let's define the direction of motion as the positive direction, so:

Fnet = -μmg
ma = -μmg
a = -μg

Now you have an acceleration that you can plug into your kinematic equations (vo is given as +1.4 m/s) to find the time to rest (v = vo+at is all you need for that).
 

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