Chem/Math Help: Solving Glaucoma Rx

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Homework Help Overview

The discussion revolves around a chemistry and mathematics problem involving the preparation of a specific eye drop solution for a glaucoma patient. The pharmacist needs to create 16 milliliters of a solution containing 5% active ingredient using available 10% and 1% solutions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between the volumes of the two solutions needed to achieve the desired concentration. They set up equations based on the total volume and the required amount of active ingredient.

Discussion Status

Some participants have attempted to solve the equations but express uncertainty about the calculations, particularly regarding the amount of active ingredient. There are indications of confusion over the arithmetic involved, and one participant questions the correctness of the initial calculations.

Contextual Notes

There is mention of a requirement to express answers as improper fractions, which adds a layer of complexity to the problem-solving process. Some participants have noted discrepancies in their results, leading to further questioning of their approaches.

Zed
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Chem/Math ! Help !

Hi ,

This is a Hw question i have am stuck on i don't know how to solve it ...

A pharmacist is to prepare 16 milliliters of special eye drops for a glaucoma patient. The eye-drop solution must have a 5% active ingredient, but the pharmacist only has 10% solution and 1% solution in stock.


How much of 10% solution should be used to fill the prescription?

How much of 1% solution should be used to fill the prescription?


please help

thx
 
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Let x be the amount of 10% solution, in ml, and let y be the amount of 1% solution, also in ml.

"A pharmacist is to prepare 16 milliliters of special eye drops for a glaucoma patient. "
So x+ y= 16

"The eye-drop solution must have a 5% active ingredient"
In other words, the amount of the active ingredient must be 5% of 16 ml= 0.005*16= 0.08 ml.
The amount of active ingredient in x ml of a 10% solution is 0.1x.
The amount of active ingredient in y ml of a 1% solution is 0.01y

We must have 0.1x+ 0.01y= 0.08.

Solve x+ y= 16 and 0.1x+ 0.01y= 0.08 for x and y.
 
Shouldn't that be 0.05*16=0.8?
 
HallsofIvy said:
Let x be the amount of 10% solution, in ml, and let y be the amount of 1% solution, also in ml.

"A pharmacist is to prepare 16 milliliters of special eye drops for a glaucoma patient. "
So x+ y= 16

"The eye-drop solution must have a 5% active ingredient"
In other words, the amount of the active ingredient must be 5% of 16 ml= 0.005*16= 0.08 ml.
The amount of active ingredient in x ml of a 10% solution is 0.1x.
The amount of active ingredient in y ml of a 1% solution is 0.01y

We must have 0.1x+ 0.01y= 0.08.

Solve x+ y= 16 and 0.1x+ 0.01y= 0.08 for x and y.


thankx for ur reply ...

after solving it i got 0.8/0.09 but still its giving me answer wrong :S.. i tried solving this way before too still wrong.. although it says to write the answer as an improper fraction. how can i write a decimal as an improper fraction !

thx

Note i did use 5% of 16 as 0.8 so..i don't thinkt hats the problem
 
ok i found x and it turned out to be correct 7.111111111 which is equivelant to 7 and 1/9 as a mixed number...

am found y but its giving me wrong answer.. please tell me if am getting y wrong... i got y to be 8.888888889
 
apmcavoy said:
Shouldn't that be 0.05*16=0.8?

Hey, arithmetic isn't my strong suit!

(And I couldn't find my calculator.)
 

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