Solve Equilibrium Problem: Biceps Force at Elbow

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The equilibrium problem involves calculating the force exerted by Misako's biceps muscle while she exerts a force on a test strap. The strap is positioned 28 cm from the elbow pivot, while the biceps muscle attachment is 5 cm from the pivot. Using the torque equation, Torque = Force x Distance, the force exerted by the biceps muscle is determined to be approximately 22.15 N when the scale reads 18 N. This calculation confirms the principles of torque and equilibrium in biomechanics.

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Misako wishes to measure the strength of her biceps muscle by exerting a force on a test strap. The strap is 28 cm from the pivot point at the elbow, and her biceps muscle is attached at a point 5 cm from the pivot point. If the scale reads 18 N when she exerts her maximum force, what force is exerted by the biceps muscle?

See attachment for a diagram. Please help me solve this problem.
 

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Try summing the moments about the elbow. Since the arm is in equilibrium, they should sum to zero; that is how to find the unknown bicep force.
 


To solve this equilibrium problem, we will use the concept of torque. Torque is the product of force and the distance from the pivot point, and it is a measure of the rotational force or moment.

In this scenario, the biceps muscle is exerting a force on the test strap, which is 28 cm away from the pivot point at the elbow. The biceps muscle is attached at a point 5 cm away from the pivot point. This means that the distance between the biceps muscle and the pivot point is 23 cm (28 cm - 5 cm).

To find the force exerted by the biceps muscle, we will use the following equation:

Torque = Force x Distance

Since we know that the scale reads 18 N when Misako exerts her maximum force, we can set up the following equation:

18 N x 28 cm = Force x 23 cm

Solving for the force, we get:

Force = (18 N x 28 cm)/23 cm

Force = 22.15 N

Therefore, the force exerted by Misako's biceps muscle is approximately 22.15 N.
 

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