Proof by Induction: Understanding D/dx Formula

  • Thread starter Thread starter sony
  • Start date Start date
  • Tags Tags
    Induction Proof
Click For Summary

Homework Help Overview

The discussion revolves around understanding the differentiation of a formula derived from proof by induction, specifically for the expression d^n/dx^n (1/x^2). Participants are exploring the application of derivatives and the reasoning behind certain transformations in the context of calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to differentiate the expression (-1)^n * (1+n)! * x^-(n+2) and are questioning the steps involved in this process. There is confusion regarding the application of the derivative and the origin of specific terms in the differentiation process.

Discussion Status

Some participants have provided insights into the essence of proof by induction, while others are still grappling with the differentiation of the expression. There is an acknowledgment of the need for clarification on how certain terms arise during differentiation, indicating an ongoing exploration of the topic.

Contextual Notes

Participants express frustration over the lack of detailed explanations in their textbook regarding the differentiation process, particularly concerning the transition from one term to another. This highlights a potential gap in understanding the foundational concepts of derivatives.

sony
Messages
102
Reaction score
0
Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

My book gives an example: (from d/dx (1+x)^-1)
d/dx [(-1)^k * k!(1+x)^(-k-1)] = (-1)^k * k!(-k-1)(1+x)^(-k-2)=...

What on Earth is going on?! My book just drops explaning _how_ . Where does (-k-1) come from? I'm stuck...

Thanks
 
Physics news on Phys.org
sony said:
Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

My book gives an example: (from d/dx (1+x)^-1)
d/dx [(-1)^k * k!(1+x)^(-k-1)] = (-1)^k * k!(-k-1)(1+x)^(-k-2)=...

What on Earth is going on?! My book just drops explaning _how_ . Where does (-k-1) come from? I'm stuck...

Thanks


the essence of proof by induction is to show that

a) there is a minimum case where what you want to prove is true
b) that if n=k is true, it follows automatically (after some manipulation) that n=k+1 is true.

there is a theorem that says that if these conditions are satisfied, the statement in question is true.


so the authors are trying to show that n=k implies that n=k+1.
 
Brad Barker said:
the essence of proof by induction is to show that

a) there is a minimum case where what you want to prove is true
b) that if n=k is true, it follows automatically (after some manipulation) that n=k+1 is true.

there is a theorem that says that if these conditions are satisfied, the statement in question is true.


so the authors are trying to show that n=k implies that n=k+1.
Yes I get _that_ :)

But how do I do the derivative of that expression?
 
sony said:
Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

Reread the chapter on derivatives. (d/dx)(x^n) = n*x^(n-1).
 
Nevermind, it was how to get from (-1)^k to (-1)^k+1 and the faculty thing I didnt get.
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
2K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
25
Views
4K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K