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hope to get the idea on how to solve this question.
the complex number z is given by
z = 1 + cos (theta) + i sin (theta)
where -pi < theta < or = +pi
show that for all values of theta, the point representing z in a Argand diagram is located on a circle. find the centre and radius of the circle.
HallsofIvy
Nov14-03, 11:38 AM
If z = 1 + cos (θ) + i sin (&theta)
Then z-1= cos(&theta)+ i sin(θ).
If you represent z as x+ iy then
(x-1)+ iy= cos(θ)+ i sin(θ)
or x- 1= cos(θ), y= sin(θ)
Those are parametric equations of a circle with what center and radius?
ok. i compare those with the
y=r sin (&theta)
and
x=r cos (&theta)
so, i know the radius = 1 unit
but may i know how to find the centre of the circle?
tq.
HallsofIvy
Nov15-03, 08:53 AM
It's exactly where the center of the circle given by
x= r cos θ
y= r sin θ is!
Hint: x2= r2cos2θ
y2= r2sin2θ
What is x2+ y2?
If that's too complicated, what is (x,y) when θ= 0?
What is (x,y) when θ= π?
tq. u helped me solved the problem.
but there is another part of the question which i ahain need some idea.
--> prove that the real part of (1/z) is (1/2) for all values of [the]
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