Proving Graph G Connectivity After Removing Arc (i,j)

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Discussion Overview

The discussion centers on proving the connectivity of a directed graph G after the removal of an arc (i,j). Participants explore the conditions under which the graph remains connected, particularly focusing on the relationship between the arc and cycles within the graph.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant poses the problem of proving that graph G remains connected after deleting arc (i,j) if and only if arc (i,j) is part of some cycle in G.
  • Another participant suggests that if arc (i,j) is part of a cycle, then a path still exists from node i to node j after its removal.
  • A participant acknowledges the existence of a path between nodes i and j but expresses difficulty in formulating a formal proof for both the "if" and "only if" conditions.
  • One suggestion involves labeling the nodes and demonstrating the existence of a spanning tree.
  • Another participant interprets the implication of deleting an arc from a cycle as the existence of a subgraph that includes all nodes of the original graph G and some of its arcs.
  • A participant describes a scenario where deleting an arc still allows for a path between its endpoints, emphasizing the transitive nature of connectivity in the graph.

Areas of Agreement / Disagreement

Participants express varying interpretations of the conditions under which connectivity is maintained after arc removal. No consensus is reached on a formal proof or the best approach to demonstrate the claims.

Contextual Notes

Participants do not fully resolve the mathematical steps necessary for the proof, and assumptions regarding the structure of the graph and cycles remain implicit.

jetoso
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I am having problems to prove this: Show that a graph G remains connected even after deleting an arc (i,j) iff arc (i,j) belongs to some cycle in G.
Grapgh G = (N, A), N = set of points of nodes, and A = set of arcs; an arc is an edge from node i to a different node j from N.

Any suggestions?
 
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You've deleted arc(i,j) but arc(i,j) is part of a cycle, so can you see that there still exists a path from i to j?
 
Yes, in fact there still is one path between them. But my problem is trying to find a formal proof to show the if condition and the only if condition as well.
 
label the nodes. and then show that there exists a spantree
 
Oh, do you mean that deleting one arc from a cycle implies that there is a subgraph such that it includes all the nodes of the original graph G and some of the arcs of it?
 
If we delete the arc A that has end points x and y and it is still connected, then there is still a path from x to y, call it B, and tehn the union of A and B is...

conversely, if there is a cycle C and we remove some edge from between x and y then it is still connected since the resulting graph is the union of the connected component containing x, the connected component containing y, and x and y are still connected by the complement ot the removed edge in the arc.

connectivity is transitive: if r is connnected to s and s is connected to t then r is connected to t.
 

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