How Far Will a Box Slide with a Coefficient of Kinetic Friction of 0.23?

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Homework Help Overview

The discussion revolves around a physics problem concerning the distance a box will slide given a coefficient of kinetic friction of 0.23 and an initial speed of 4.2 m/s. The context suggests a focus on the effects of friction and initial velocity on motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relevance of the initial speed and the coefficient of kinetic friction, with some questioning how these factors interact without additional information such as the object's weight. Others reference a similar problem to draw parallels and seek clarification on the reasoning behind the solution.

Discussion Status

The conversation is ongoing, with some participants expressing confusion about the relationship between the given parameters and the solution. There is an acknowledgment of a similar problem that may provide insight, but no consensus has been reached on the approach to take. Guidance has been offered regarding potential methods, but participants are still exploring their understanding.

Contextual Notes

Participants note that they lack certain information, such as the object's weight, which may be critical for solving the problem. There is also mention of differing levels of familiarity with relevant equations and methods, indicating a range of understanding among participants.

jshaner858
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If the coefficient of kinetic friction of a box is 0.23, how would you find out how far the box would travel with an initial push of 4.2 m/s? Assume the "push" has already happened.
 
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it's a different problem...that's all the info I've been given...i don't know how the speed factors into the problem...i don't know the object's weight or anything else
 
did you read the solution, there's no mass involved.

"A box is given a push so that it slides across the floor. How far will it go given that the coefficient of kinetic friction is .20 and the push imparts an initial speed of 4.0 m/s?"

go back and actually read it. this problem is identical to yours. Then tell me where your getting stuck, if you do get stuck.
 
the answer to the problem you wrote is actually 4.1 meters but i don't know how that answer was reached
 
read the solution i posted! lol, don't sweat it will work it out together, just tell me if you have learned energy methods yet or not, so I will know which approach is appropriate.
 
and how did you happen to change the numbers around so that they were identical to a problem in my textbook?
 
which method do you want to use jshaner?
 
thanks...i'm sorry i didn't see the link that you put up there...thanks so much...i was able to get the answer, but those equations are a little beyond where we're at right now...thanks again.
 
  • #10
well, they are really quite simple, as long as you know basic calculus. and its very straight forward, we can go over them if you would like.
 

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