Is a Vector e=(0,1) a Basis in R^2?

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SUMMARY

The vector e=(0,1) cannot serve as a basis in R^2 because a basis requires two linearly independent vectors in a two-dimensional space. The discussion confirms that for any vector u expressed as u=a(0,1), it lacks the necessary dimensionality to span R^2. Therefore, the conclusion is that a single vector cannot form a basis in a two-dimensional vector space.

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sibiryk
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I am not sure if a vector e=(0,1) is a basis in R^2.

Can it give an expansion to vector u:

u=a(0,1)

u1=0
u2=a ?
 
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I got it. It a was a stupid question.
 
R2 is "2 dimensional" and so requires 2 vectors for a basis.
 

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