What Went Wrong in Calculating the Volume of Gas from Decomposition?

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Homework Help Overview

The problem involves calculating the volume of oxygen gas produced from the decomposition of hydrogen peroxide, specifically using the reaction 2H2O2(aq) ---> 2H2O(l) + O2(g). The original poster presents their calculations based on a given mass of hydrogen peroxide solution and temperature and pressure conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the volume of oxygen produced using the ideal gas law after determining the moles of hydrogen peroxide. Participants question the stoichiometry of the reaction and the calculations leading to the volume results.

Discussion Status

Participants are exploring the calculations and assumptions made by the original poster, with some suggesting potential errors in stoichiometry and others expressing confusion about the correctness of the initial volume calculation. There is no clear consensus on the accuracy of the calculations presented.

Contextual Notes

Some participants note issues with the problem set and the reliability of answers provided by teaching assistants, indicating a broader concern about the accuracy of homework problems and solutions.

Pengwuino
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So here's the problem I am faced with... dum dum dummmm

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe):

2H2O2(aq) ---> 2H2O(l) + O2(g)

What volume of pure O2(g), collected at 27 °C and 746 torr, would be generated by decomposition of 61.2 g of a 50.0 % by mass hydrogen peroxide solution? Ignore any water vapor that may be present.

So first I figured that there will be 30.6g of hydrogen peroxide. Then I figured that there are 0.4498 moles of O2. Then using the ideal gas law...

V=nRT/P

I got ((0.4498)(0.08206)(27+273.15))/(746/760) = 11.3 Liters of O2

But supposedly I am wrong. Where did I go so horribly horribly wrong?

Oops, and i just punched in 22.6 Liters and it says I'm right... so where did I divide by 2 where I shouldn't have?
 
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It's impossible to locate your error since you have not shown your work.
 
Pengwuino said:
So here's the problem I am faced with... dum dum dummmm



So first I figured that there will be 30.6g of hydrogen peroxide. Then I figured that there are 0.4498 moles of O2. Then using the ideal gas law...

V=nRT/P

I got ((0.4498)(0.08206)(27+273.15))/(746/760) = 11.3 Liters of O2

But supposedly I am wrong. Where did I go so horribly horribly wrong?

You didn't read/remember the stoichiometry of the decomposition.
Oops, and i just punched in 22.6 Liters and it says I'm right... so where did I divide by 2 where I shouldn't have?

22.6? Gotta be a TA solving the problem sets --- and getting wrong answers, as is usual. You've been told where you didn't divide by two when you should have, and it's probably the same place the TA multiplied mistakenly.
 
Tom Mattson said:
It's impossible to locate your error since you have not shown your work.

Everything was already given, all I had to do was punch in the numbers. All i needed was moles and the temperature conversion and both were done correctly. The R constant is correct as well.
 
Bystander said:
22.6? Gotta be a TA solving the problem sets --- and getting wrong answers, as is usual. You've been told where you didn't divide by two when you should have, and it's probably the same place the TA multiplied mistakenly.

So 11.3 was correct?

I've been noticing a few of these problems are absolutely wrong lately in the homework. One problem had a very simple PV=nRT problem, EVERYTHING except 1 variable was missing and I did it and couldn't figure out the right answer. I show it to 4 other people... one about to graduate with his bs in physics, one his masters in physics, and 2 other people and no one could figure out what was wrong. The answer made sense (small volume, low pressure, normal temperature meant even smaller moles value) and it wasn't acording to the homework program.
 
Mole of peroxide yields half mole of O2. It's called a sitting duck.

Collateral duties of TAs include solving problem sets, checking answer keys, and keeping keys up to date when instructors change the numbers from year to year to defeat the frat-rat files --- these duties are usually performed in lackluster fashion, if at all.

Your job as a student is to bring necessary corrections to TAs' and instructors' attentions in as diplomatic a fashion as possible --- if they don't take it gracefully, you've got end of term evaluation forms.
 
Bystander said:
Your job as a student is to bring necessary corrections to TAs' and instructors' attentions in as diplomatic a fashion as possible --- if they don't take it gracefully, you've got end of term evaluation forms.

Well was I right with the first calculation (11.3)?? I am getting a little confused by everyone here :P
 
Half mole, 11 liters, yes.
 

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